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anygoal [31]
3 years ago
6

I really need help ASAP PLEASEEEE !!

Mathematics
1 answer:
STALIN [3.7K]3 years ago
4 0
It would be 270,725. The last choice.
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Which expressions are equivalent to the equation
Ivahew [28]

Answer:

The correct answer is option 3

2⁻¹⁰ and 1/1024

Step-by-step explanation:

Points to remember

1). ( xᵃ)ᵇ = xᵇ

2).  x⁻ᵃ = 1/xᵃ

It is given that, (2⁵)⁻²

<u>To find the equivalent of (2⁵)⁻²</u>

(2⁵)⁻² =  2⁻¹⁰

<u>To find the value of 2⁻¹⁰</u>

2⁻¹⁰ = 1/2¹⁰

2¹⁰ = 1024

1/2¹⁰ = 1/1024

Therefore the correct answer is 3rd option

2⁻¹⁰ and 1/1024

5 0
3 years ago
Read 2 more answers
Consider the parabola whose equation is y=x^2-4x and the line whose equation is y=2x+b, where b is some unknown constant
Vikki [24]

Answer:

Step-by-step explanation:

Is there a question somewhere in there?

6 0
3 years ago
While driving from​ Chicago, Brent had a visibility problem due to the fog. After 1 1/2
liq [111]
1) Let x be the original speed that he was driving; 

x mph ---> 1.5 hours 
x+44 mph --> 2.5 hours 

1.5x + 2.5(x+44)=206 
1.5x+2.5x+110=206 
4x=206-110 
4x=96 
x=24 
Therefore, he was travelling at 24 mph in the fog. 

2) Let x be the speed of 1 snail, 
The other snail travels at the speed of x+1 cm/min 

23x+23(x+1)=391 <-- solve for x 
23x+23x+23=391 
46x=368 
x=368/46 
x=8 

Therefore one of the snail travels at 8 cm/min while the other goes at 9 cm/min 

7) Let x be one crew 
Then the other crew would be working at x+0.5 

3.2x+3.2(x0.5)=8 <-- solve for x 
3.2x+1.6x=8 
4.8x=8 
x=8/4.8 
x=1.6666 or 1.7 miles 

Therefore, one of the crew does 1.7 miles per day and the other crew does (0.5*1.7)=0.85 miles

Hope I helped :) 
5 0
4 years ago
Businesses deposit large sums of money into bank accountsImagine an account with $10 million dollars in it.
adoni [48]

again, let's assume daily compounding means 365 days per year.

~~~~~~ \textit{Simple Interest Earned} \\\\ I = Prt\qquad \begin{cases} I=\textit{interest earned}\\ P=\textit{original amount deposited}\dotfill & \$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ t=years\dotfill &1 \end{cases} \\\\\\ I = (10000000)(0.0212)(1)\implies \boxed{I=212000}

~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$10000000\\ r=rate\to 2.12\%\to \frac{2.12}{100}\dotfill &0.0212\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{daily, thus 365} \end{array}\dotfill &365\\ t=years\dotfill &1 \end{cases}

A=10000000\left(1+\frac{0.0212}{365}\right)^{365\cdot 1}\implies A\approx 10214256.88 \\\\\\ \underset{\textit{earned interest amount}}{10214256.88~~ - ~~10000000 ~~ \approx ~~ \boxed{214256.88}}

what's their difference?  well

\stackrel{\textit{compounded daily}}{\approx 214256.88}~~ - ~~\stackrel{\textit{simple interest}}{212000}\implies \boxed{2256.88}

7 0
2 years ago
Please help with this! Jen is deciding to get a new phone. One deal is a free phone with a two year contract, but she will have
Gnom [1K]
All you have to do is add 399 to 10 and then multiply by ten. Then you get 199 and multiply by .08 and multiply that by ten. Then you subtract.
7 0
3 years ago
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