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3 years ago

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Find the line parallel to 5x-4y=8 that passes through points 3,-2

1 answer:

navik [9.2K]3 years ago

5 0

That's the answer to this question.

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If three-fifths of seventh-grade class has missed at least one day of school, what percentage of 7th grade has missed at least a

jeyben [28]

Cronchy monchy
bonkier wonkiers 89%

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3 years ago

Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

blsea [12.9K]

Answer:

a) Percentage of students scored below 300 is 1.79%.

b) Score puts someone in the 90th percentile is 638.

Step-by-step explanation:

Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.

(a) If the average test score is 510 with a standard deviation of 100 points.

To find : What percentage of students scored below 300 ?

Solution :

Mean $\mu=510$ ,

Standard deviation $\sigma=100$

Sample mean $x=300$

Percentage of students scored below 300 is given by,

$P(Z\leq \frac{x-\mu}{\sigma})\times 100$

$=P(Z\leq \frac{300-510}{100})\times 100$

$=P(Z\leq \frac{-210}{100})\times 100$

$=P(Z\leq-2.1)\times 100$

$=0.0179\times 100$

$=1.79\%$

Percentage of students scored below 300 is 1.79%.

(b) What score puts someone in the 90th percentile?

90th percentile is such that,

$P(x\leq t)=0.90$

Now, $P(\frac{x-\mu}{\sigma} < \frac{t-\mu}{\sigma})=0.90$

$P(Z< \frac{t-\mu}{\sigma})=0.90$

$\frac{t-\mu}{\sigma}=1.28$

$\frac{t-510}{100}=1.28$

$t-510=128$

$t=128+510$

$t=638$

Score puts someone in the 90th percentile is 638.

5 0

3 years ago

Determine the number of possible outcomes when tossing one coin ,two coins ,and three coins then determine the number of possibl

m_a_m_a [10]

Number of possible outcome for tossing N coins = $2^N$

Solution:

Possible outcomes when tossing one coin = {H, T}

Number of possible outcomes when tossing one coin = 2 $=2^1$

Possible outcomes when tossing two coins = {HH, HT, TH, TT}

Number of possible outcomes when tossing two coins = 4 $=2^2$

Possible outcomes when tossing three coins

= {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}

Number of possible outcomes when tossing three coins = 8 $=2^3$

Therefore, the sequence obtained is $2^1, 2^2, 2^3$ .

If continue this sequence, we can obtain number of possible outcome for tossing N coins is $2^N$ .

7 0

3 years ago

I need help man

solong [7]

Answer:

65x + y = 60

Step-by-step explanation:

hope it will help you

4 0

3 years ago

Can u plz help me in this plz?

Yanka [14]

There isn’t a picture what do you need help with

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3 years ago