You need to use Pythagoras’ Theorem.
A² + B² = c² and c is the hypotenuse of the right angled triangle.
The height of the tower (5 feet) is A and the distance from the end of the cable and the base of the tower (12 feet) is B. The length of ONE cable is c. So:
A² + B² = c²
5² + 12² = c²
25 + 144 = c²
169 = c²
13 = c. This is the length of one cable.
3 x 13 = 39 therefore the total length of the cables is 39 feet.
25
Answer:
The length of the longest section x = 36 ft
Step-by-step explanation:
Total length of the wire = 51 ft
Let first section of wire = x
Second section of wire = y
Third section of wire = z
According to given data
x = 3 y & y = 4 z
Total length of the wire = x + y + z = 51


y = 12
x = 3 × 12 = 36

Therefore the length of the longest section x = 36 ft
Answer:
A
Step-by-step explanation: just divide 71 into 2 which gives you 35.5 making a your answer.
I think it's 1/2, which is 6/12.
5/12 plus 1/12 equals 6/12. 6 is half of 12, so you one half. I hoped this helped.
Use the tangent-chord theorem:
The included chord-tangent angle is half the size of the intercepted arc.
The intercepted arc is "c".
The included chord-tangent-angle is the supplement of 110=70 degrees.
Therefore from the tangent-chord theorem, 70 degrees = half the size of arc "c"
=>
arc "c" = 2*intercepted angle = 2*70 degrees = 140 degrees.