By Kirchoff's law in left side loop

similarly kirchoff's law in right side loop

also by junction law we know that

now by plug in all values we have




So by solving above equations we have



Answer:
Explanation:
A lot. That's why he was one of Boston's star hitters.
m = 0.15 kg
a = 3.0 * 10^4
F = ?
F = 0.15 * 3*10^4
F = 0.45 * 10^4
F = 4.5 * 10^3 Newtons
You should always express scientific notation as a number between 1 and 10 or 1 < x < 10. The power will determine the exact value of the number expressed as a scientific notation.
Answer:
See answer
Explanation:
Given quantities:
![\eta = 0.05\\ W=90[W]\\r=0.0285[m]](https://tex.z-dn.net/?f=%5Ceta%20%3D%200.05%5C%5C%20W%3D90%5BW%5D%5C%5Cr%3D0.0285%5Bm%5D)
where
is the efficiency of the lightbulb (visible light is 5% of the total power),
is the total power of the lightbulb, r is the radius of the lightbulb in meters.
Intensity is power divided by area:

a) Now the effective power is
, therefore:
![I =\frac{\eta*W}{\pi r^2}=\frac{0.05*90}{4\pi (0.0285)^2}=440.87[W/m^2]](https://tex.z-dn.net/?f=I%20%3D%5Cfrac%7B%5Ceta%2AW%7D%7B%5Cpi%20r%5E2%7D%3D%5Cfrac%7B0.05%2A90%7D%7B4%5Cpi%20%280.0285%29%5E2%7D%3D440.87%5BW%2Fm%5E2%5D)
b) Now the intensity is the average poynting vector is related to the magnitudes of the maximum electric field and magnetic field amplitudes, following:
![S_{average}= \frac{EB}{2\mu_{0}}[W/m]](https://tex.z-dn.net/?f=S_%7Baverage%7D%3D%20%5Cfrac%7BEB%7D%7B2%5Cmu_%7B0%7D%7D%5BW%2Fm%5D)
now
and
are related:
and 
replace in 
![S_{average}=I= \frac{c \epsilon_{0}E^2}{2}[W/m]](https://tex.z-dn.net/?f=S_%7Baverage%7D%3DI%3D%20%5Cfrac%7Bc%20%5Cepsilon_%7B0%7DE%5E2%7D%7B2%7D%5BW%2Fm%5D)
we replace the values and we get:

![E = \sqrt{\frac{2(440.8)}{8.85*10^{-12}3*10^8}}=576.24[V/m]](https://tex.z-dn.net/?f=E%20%3D%20%5Csqrt%7B%5Cfrac%7B2%28440.8%29%7D%7B8.85%2A10%5E%7B-12%7D3%2A10%5E8%7D%7D%3D576.24%5BV%2Fm%5D)
therefore
![B=\frac{E}{c}=\frac{576.24}{3*10^{8}}=1.92*10^{-6}[T]](https://tex.z-dn.net/?f=B%3D%5Cfrac%7BE%7D%7Bc%7D%3D%5Cfrac%7B576.24%7D%7B3%2A10%5E%7B8%7D%7D%3D1.92%2A10%5E%7B-6%7D%5BT%5D)
Technician A is Correct.
You can see this when he says that conductors have more free electrons than insulators. This statement is True.
While Technician B says that, insulators have the lower resistance than conductors. This statement is False.