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Elina [12.6K]
3 years ago
7

A tuning fork with a frequency of 675 Hz resonates in an air column when the length of the tube is 17.0 cm and again when the le

ngth is 43.0 cm. The wavelength of the standing wave in the air column is ___cm

Physics
1 answer:
maria [59]3 years ago
8 0

Answer:

Explanation:

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Set kinetic energy equal to potential energy and solve for velocity
nikdorinn [45]
KE = PE
1/2 m • v^2 = mgh
1/2 • v^2 = gh
V^2/2 = gh
2 • (v^2/2) = 2 • (gh)
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4 years ago
You have just landed your first job as a structural engineer and you have been asked to design a regional airport for small plan
lidiya [134]

Answer: 197.40\ m

Explanation:

Given

final velocity at takeoff v=28.1\ m/s

Acceleration of the plane can be a=2\ m/s^2

Initial velocity is zero for the plane i.e. u=0

Using the equation of motion

\Rightarrow v^2-u^2=2as\quad [\text{s=displacement}]\\\text{Insert the values}\\\Rightarrow (28.1)^2-0=2\times 2\times s\\\\\Rightarrow s=\dfrac{789.61}{4}\\\\\Rightarrow s=197.40\ m

Thu,s the minimum length must be 197.40\ m

6 0
3 years ago
Why is velocity squared in kinetic energy and mass multiplied by 1/2?
maxonik [38]
Remember the definition of work done.
Work done is force(F) times displacement(x)
∴ W = F.Δx 
According to Newton's 2nd law of motion,

F = ma
∴ W = ma.Δx ---- (i)
Using the kinematical equation v²-u² = 2ax,
aΔx = (v²-u²)/2 

Plug this value in (i),

∴W = m[\frac{v^{2}-u^{2}  }{2}]
∴W = \frac{mv^{2} }{2} -  \frac{mu^{2} }{2}

Which is nothing but change in kinetic energy.
That is how kinetic energy is derived 
5 0
3 years ago
A uniform electric field, with a magnitude of 650 N/C, is directed parallel to the positive x-axis. If the potential at x = 3.0
noname [10]

Answer:

Explanation:

Given that,

Electric Field is

E = 650 N/C

The potential at x1 = 3 is

V1 = 1700V

What is the potential at x2 = 1

V2 =?

Electric potential is given as

V = Ed

Then,

E = V/d

Therefore, the electric field is gradient of the potential and the position.

So,

E = —∆V / ∆x

E = — (V2 — V1) / (x2 — x1)

E = —(V2—1700) / (1—3)

650 = — ( V2—1700) / -2

650 × -2 = —V2 + 1700

-1300 = -V2 + 1700

V2 = 1700+1300

V2 = 3000 V

5 0
3 years ago
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