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Pavel [41]
4 years ago
14

Which statement is always false for athletes participating in team sports?

Physics
1 answer:
tatyana61 [14]4 years ago
3 0
Which statement is always false for athletes participating in team sports?

Answer: Out of all the options shown above the one that best represents the statement that is alway false for athletes participating in team sports is answer choice C) Conflict resolution is a sign of poor sportsmanship. All the other choices are true when it comes to team sports.

I hope it helps, Regards.
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While practicing the trumpet you notice that every time you play a particular note a window in the room rattles. How can you exp
kherson [118]
The sound waves travel because of the pitch of the note so the window rattles.
7 0
3 years ago
How much does Earth weight?​
frutty [35]

Answer:

About 13, 000,000,000,000,000,000,000,000 pounds.

Explanation:

4 0
3 years ago
Read 2 more answers
An object has a mass of 15 kg and is accelerating to the right at 16.3 m/s2. The free-body diagram shows the horizontal forces a
marshall27 [118]
Refer to the free body diagram shown melow.

F =  applied force
R =  frictional force
m = 15 kg, the mass of the object

The acceleration (to the right) is 16.3 m/s², therefore
F - R = (15 kg)*(16.3 m/s²) = 244.5 N

The normal reaction is
N = mg = (15 kg)*(9.8 m/s²)  = 147 N
The frictional force is
R = μN = 147μ N,  where μ =  coefficient of kinetic friction.

Let us check possible answers:
If R = 5.5 N, then μ = 5.5/147 = 0.0374 (very likely)
If R = 15 N, then μ = 15/147 = 0.102 (possible)
If R = 244.5 N,   (Highly unlikely, exceed mg)
If R = 494.5 N, (highly unlikely, exceeds mg)

Answer:
The most reasonable answer is R = 5.5 N

8 0
3 years ago
Read 2 more answers
object carries a charge of -8.1 µC, while another carries a charge of -2.0 µC. How many electrons must be transferred from the
LenKa [72]

Number of electrons transferred: 1.91\cdot 10^{13}

Explanation:

The charge on the first object is

Q_1 = -8.1\mu C

while the charge on the 2nd object is

Q_2=-2.0 \mu C

When they are in contact, the final charge on each object will be

Q=\frac{Q_1+Q_2}{2}=\frac{-8.1+(-2.0)}{2}=-5.05 \mu C

So, the amount of charge (electrons) transferred from the 1st object to the 2nd object is

\Delta Q = Q_1 - Q = -8.1 -(5.05)=-3.05 \mu C = -3.05\cdot 10^{-6}C

The charge of one electron is

e=-1.6\cdot 10^{-19}C

Therefore, the number of electrons transferred is

N=\frac{Q}{e}=\frac{-3.05\cdot 10^{-6}}{-1.6\cdot 10^{-19}}=1.91\cdot 10^{13}

Learn more about electrons:

brainly.com/question/2757829

#LearnwithBrainly

8 0
3 years ago
How much work is done if a 50N weight is lifted to a height of 10m? ​
borishaifa [10]

500J  

Explanation:

Given parameters:

Weight of the body = 50N

Height = 10m

Unknown:

Work done = ?

Solution;

Work done is the force that moves a body through a particular distance in the direction of the force.

In this problem, we can solve the problem by relating work done to the potential energy used in lifting the mass.

  The weight on a body, a force in the presence of gravity

         weight(weight) = mg

  where m = mass of body

              g = acceleration due to gravity

  Work done = Fxd

   Where F = force on the body

               d = distance moved

Potential energy = mgh

    where h is the height

     P.E = work done =  Weight x height = 50 x 10 = 500J  

Learn more:

Work done brainly.com/question/9100769

#learnwithBrainly

6 0
3 years ago
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