Calculate the magnitude of the normal force acting on a 20 kg block the block is resting on the surface of an elevator accelera
1 answer:
Answer:
Fn = 246.2 N
Explanation:
I assume you meant meters per second squared for acceleration of the elevator. All you have to after your picture/free-body diagram is made is add the forces together. You could do this by finding them separately like I did or use Fn = m(Fg + Fe). I just calculated magnitude and didn't worry about signs.
You might be interested in
Answer:
The component form will be;
In the x-axis = 121.73 due west
In the y-axis = 690.35 due south
Explanation:
An image of the calculation has been attached
