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alexandr402 [8]
3 years ago
12

Calculate the magnitude of the normal force acting on a 20 kg block the block is resting on the surface of an elevator accelera

ting 2.5m/s
Physics
1 answer:
wlad13 [49]3 years ago
8 0

Answer:

Fn = 246.2 N

Explanation:

I assume you meant meters per second squared for acceleration of the elevator.  All you have to after your picture/free-body diagram is made is add the forces together.  You could do this by finding them separately like I did or use Fn = m(Fg + Fe). I just calculated magnitude and didn't worry about signs.

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what mass of lead has the same volume as 1600 of alcohol ( density of lead =11300kg\m³ and density of alcohol=790kg\m³)​
Misha Larkins [42]

The mass of lead = 22,939 kg

<h3>Further explanation</h3>

Given

mass alcohol=1600 kg

The density of lead =11300kg\m³ and density of alcohol=790kg\m³

Required

mass of lead

Solution

  • volume of alcohol

\tt V=\dfrac{mass}{\rho}\\\\V=\dfrac{1600}{790}\\\\V=2.03~m^3

the volume of lead=volume of alcohol=2.03 m, so the mass of lead :

\tt m=\rho\times V\\\\m=11300\times 2.03\\\\m=22,939~kg

7 0
3 years ago
Block A, with a mass of 4.0 kg, is moving with a speed of 2.0 m/s while block B , with a mass of 8.0 kg, is moving in the opposi
Anon25 [30]
Consider velocity to the right as positive.

First mass:
m₁ = 4.0 kg
v₁ = 2.0 m/s to the right

Second mass:
m₂ = 8.0 kg
v₂ = -3.0 m/s to the left

Total momentum of the system is
P = m₁v₁ + m₂v₂
   = 4*2 + 8*(-3)
  = -16 (kg-m)/s

Let v (m/s) be the velocity of the center of mass of the 2-block system.

Because momentum of the system is preserved, therefore
(m₁+m₂)v= -16
(4+8 kg)*(v m/s) = -16 (kg-m)/s
v = -1.333 m/s

Answer:
The center of mass is moving at 1.33 m/s to the left.
5 0
3 years ago
A 1200 kg car traveling at 60 mph quickly brakes to a halt. The kinetic energy of the car is converted to thermal energy of the
ololo11 [35]

Answer:

 ΔT = 59.9 ° C

Explanation:

For this exercise the brake energy is totally converted into heat

Let's calculate the vehicle energy

       K = ½ m v²

Let's reduce the units to the SI system

       v = 30 mph (1609.34 m / mile) (1h / 3600s) = 13.41 m / s

      Em = K = ½ 1200 13.41²

      K = 1.079 105 J

All this energy is transformed into heat

     Em = Q

The expression for heat is

     Q = m  c_{e} ΔT

     ΔT = Q / m c_{e}

The specific heat of iron is c_{e} = 450 J / Kg ºC

     ΔT = 1,079 105 / (4.0 450)

     ΔT = 59.9 ° C

8 0
3 years ago
Read 2 more answers
Something is thrown in the air and 5.35 seconds later it lands on something 2.1 meters from the ground. How fast was it thrown u
UNO [17]

Answer:

26.6 m/s

Explanation:

Given:

Δy = 2.1 m

t = 5.35 s

a = -9.8 m/s²

Find: v₀

Δy = v₀ t + ½ at²

(2.1 m) = v₀ (5.35 s) + ½ (-9.8 m/s²) (5.35 s)²

v₀ = 26.6 m/s

5 0
3 years ago
Has a definite shape and definite volume. Question 4 options: liquid gas solid
ad-work [718]

Answer:

solid

Explanation:

solid

3 0
3 years ago
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