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Delvig [45]
3 years ago
13

Please help me with this question!!!

Mathematics
1 answer:
andreev551 [17]3 years ago
3 0

Answer:

565.94

Step-by-step explanation:

A=2 π r h+2 π r^2   --- formula

I think this is correct

You might be interested in
a un baile asistieron 270 personas.si los boletos de costaban 100 pesos y los de dama 80 pesos y se recaudaron 24 800 pesos por
ser-zykov [4K]
The question in English
<span>A dance was attended by 270 people. If the gentlemen tickets cost 100 pesos and the lady tickets 80 pesos and 24800 pesos were collected for all the tickets. How many women and how many men attended the dance?

let
x---------> the number of men
y--------> the number of women

we know that
x+y=270----> x=270-y-----> equation 1
100x+80y=24800-------> equation 2
substitute equation 1 in equation 2
100*[270-y]+80y=24800----> 27000-100y+80y=24800
20y=2200-----> y=110
x=270-y----> x=270-110----> x=160

the answer is
the number of men ---> 160
the number of women----> 110

the answer in Spanish

</span>hagamos
x--------->la cantidad de hombres
y--------->la cantidad de mujeres

Sabemos que
x+y=270----> x=270-y-----> ecuacion 1
100x+80y=24800-------> ecuacion 2
sustituimos la ecuacion 1 en la ecuacion 2
100*[270-y]+80y=24800----> 27000-100y+80y=24800
20y=2200-----> y=110
x=270-y----> x=270-110----> x=160

La respuesta es
la cantidad de hombres es 160
la cantidad de mujeres es 110
4 0
3 years ago
an electronics store had 182 video games. if they put them on shelves with 24 on each shelf, about how many shelves would they n
GalinKa [24]
182 games 24 on each shelf basicaaly x shelves is more than or equal to 182 games 1 shelf=24 x times 24>182 divide both sides by 24 x>7 and 4/24 x has to be a whole number since you can't have fractional shelves you have to have more shelves since less shelves won't allow you to carry all of them round up 7 and something rounded u is 8

 8 shelves (if you are a weird store that has fractional shelves then the answer is 7 and 1/6 shelves)
5 0
3 years ago
Read 2 more answers
Megan received a $208,000 inheritance after taxes from her parents. She invested it at 8% interest compounded quarterly for 5 ye
Nookie1986 [14]
Use the compound interest formula.
  A = P*(1 +r/n)^(n*t)
where P is the principal, r is the annual rate, n is the number of compoundings per year, and t is the number of years.

For the first investment, ...
  A = 208,000*(1 +.08/4)^(4*5) = 309,077.06

For the second investment, ...
  A = 218,000*(1 +.07/2)^(2*4) = 287,064.37

Totaling both investments at maturity, Megan has $596,141.43.
3 0
3 years ago
Solve the inequality. 18 &gt; 12 + x
aleksley [76]
6>x take 12 from both sides
5 0
3 years ago
-x + 2y = 3<br> 2x – 3y = -6
s2008m [1.1K]

Answer:

x = -3

y = 0

Step-by-step explanation:

<u>Given</u><u> </u><u>equations</u><u> </u><u>:</u><u>-</u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>i</u><u> </u><u>)</u><u> </u><u> </u>

<u>-x</u><u> </u><u>+</u><u> </u><u>2</u><u>y</u><u> </u><u>=</u><u> </u><u>3</u><u> </u>

<u>-x</u><u> </u><u>=</u><u> </u><u>3</u><u> </u><u>-</u><u> </u><u>2</u><u>y</u><u> </u>

<u>x</u><u> </u><u>=</u><u> </u><u>2</u><u>y</u><u> </u><u>-</u><u> </u><u>3</u><u> </u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u>

<u>From</u><u> </u><u>(</u><u> </u><u>ii</u><u> </u><u>)</u><u> </u>

<u>2</u><u>x</u><u> </u><u>-</u><u> </u><u>3</u><u>y</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u>

<u>2</u><u>x</u><u> </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>+</u><u> </u><u>3</u><u>y</u><u> </u>

<u>x =  \frac{ - 6 + 3y}{2}</u>

<u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>Equating</u><u> </u><u>(</u><u> </u><u>iii</u><u> </u><u>)</u><u> </u><u>and</u><u> </u><u>(</u><u> </u><u>iv</u><u> </u><u>)</u>

<u>x</u><u> </u><u>=</u><u> </u><u>x</u><u> </u>

<u>2y - 3 =  \frac{ - 6 + 3y}{2}</u>

4y - 6 = -6 + 3y

4y - 3y = -6 + 6

y = 0

Putting value of y in ( iii )

x = 2y - 3

x = 2 ( 0 ) - 3

x = -3

4 0
3 years ago
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