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Fantom [35]
3 years ago
13

The area of a rectangular table top is 24 ft.² the length of the table is 2 feet longer than its width which equation could be u

sed to find the width of the table top?

Mathematics
1 answer:
Goryan [66]3 years ago
4 0

Answer: D) 24 = w^2 + 2w

Step-by-step explanation:

Hi, to answer this question we have to apply the next formula:

Area of a rectangle (A) = length (L) x width (w)

Since:

Length = w+2

Substituting: L =w+2 in the formula:

A = (w+2) w

Replacing with the value given:

24 = (w+2)w

Applying distributive property:

24 = w^2 + 2w

Feel free to ask for more if needed or if you did not understand something.

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A health food store sells a mixture of raisins and roasted nuts.
murzikaleks [220]

Answer:

Raisins = 25 kg

Nuts = 15 kg

Step-by-step explanation:

Given that:

Kilograms of snack to be made = 40 kg

Price per kg would be $4.75kg.

Price of 40 kg would be = 4.75 * 40 = $190

Let,

x be the kilograms of raisins

y be the kilograms of nuts

According to given statement;

x+y=40        Eqn 1

4.00x+6.00y=190      Eqn 2

Multiplying Eqn 1 by 4

4(x+y=40)

4x+4y=160    Eqn 3

Subtracting Eqn 3 from Eqn 2

(4x+6y)-(4x+4y)=190-160

4x+6y-4x-4y=30

2y=30

Dividing both sides by 2

\frac{2y}{2}=\frac{30}{2}\\y=15

Putting y=15 in Eqn 1

x+15=40

x=40-15

x=25

Hence,

Raisins = 25 kg

Nuts = 15 kg

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2 years ago
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Question Progress 10 Homework Progress 17/ x: y = 2:3 Which is the correct equation? A 2x = 3y B 2y = 3x C y = x - 1 D y = x + 1
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Answer:  2y = 3x

Reason:

The equation x:y = 2:3 is the same as saying x/y = 2/3

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1 year ago
Can someone help me i will give brainliest to whom ever right 28=x+13
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The answer is that x equals 15
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2 years ago
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Find the polynomial of minimum degree, with real coefficients, zeros at
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Answer:

\huge\boxed{p(x)=4x^3-20x^2+4x+300}

Step-by-step explanation:

\text{If}\ x=4\pm3i\ \text{and}\ x=-3\ \text{are the zeros of a polynomial, then it has  a form:}\\\\p(x)=\bigg(x-(4-3i)\bigg)\bigg(x-(4+3i)\bigg)\bigg(x-(-3)\bigg)\bigg(r(x)\bigg)\\\\p(x)=(x-4+3i)(x-4-3i)(x+3)\bigg(r(x)\bigg)\\\\p(x)=\underbrace{\bigg((x-4)+3i\bigg)\bigg((x-4)-3i\bigg)}_{\text{use}\ (a+b)(a-b)=a^2-b^2}(x+3)\bigg(r(x)\bigg)\\\\p(x)=\bigg((x-4)^2-(3i)^2\bigg)(x+3)\bigg(r(x)\bigg)\qquad\text{use}\ (a-b)^2=a^2-2ab+b^2

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Answer:

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