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2 years ago

Find the missing angles in the figure below.

Mathematics

2 answers:

vivado [14]2 years ago

8 0

Answer:

First option is right.

Step-by-step explanation:

w=78 (vertically opposite angles)

l=82 (vertically opposite angles)

M= 180-64=116 (linear pair)

sorry im not sure how to find y and z

SashulF [63]2 years ago

7 0

Answer: The answer is A. Just check the only answer with y=z.

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64÷54 is the number of.... whar

ankoles [38]

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3 years ago

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A math teacher keeps her wall-sized graph paper in a box shaped like a triangular prism. The triangular face of the prism has a

yaroslaw [1]

(24 × 17 × 130\2)

24 × 17 = 408 x 130 = 53,040 / 2 = 26,520
So the volume of this box is

C= 26,520 cm^3

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2 years ago

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denis23 [38]

Answer:

Step-by-step explanation:

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2 years ago

A door to a playhouse is 50 inches tall. Which of the following is another measure equal to the height?

Effectus [21]

Answer:

4 ft 2 in.

Step-by-step explanation:

A door to a playhouse is 50 inches tall

we know that

1 in---------------> is 0.0833333 ft

50 in-------------> 50*0.0833333---------> 4.167 ft

4.167 ft----------> [4 ft+0.167 ft]

remember that

1 in---------------> is 0.0833333 ft

X in----------------> 0.167 ft

X=0.167/0.0833333----------> X=2 in

4.167 ft----------> [4 ft+0.167 ft]--------> [4 ft+2 in]

5 0

2 years ago

Find the solution to this system of equations <br> 3x+2y+3z=3 4x-5y+7z=1 2x+3y-2z=6 <br> x=? Y=? Z=?

Ede4ka [16]

Answer:

The solution is $x=2,\ y=0,\ z=-1.$

Step-by-step explanation:

You are given the system of three equations:

$\left\{\begin{array}{l}3x+2y+3z=3\\4x-5y+7z=1\\2x+3y-2z=6\end{array}\right.$

Multiply the first equation by 4, the second equation by 3 and subtract them. Then multiply the third equation by 2 and subtract it from the second equation:

$\left\{\begin{array}{l}3x+2y+3z=3\\4(3x+2y+3z)-3(4x-5y+7z)=4\cdot 3-3\cdot 1\\4x-5y+7z-2(2x+3y-2z)=1-2\cdot 6\end{array}\right.\Rightarrow \\\\\left\{\begin{array}{l}3x+2y+3z=3\\12x+8y+12z-12x+15y-21z=12-3\\4x-5y+7z-4x-6y+4z=1-12\end{array}\right.$

So,

$\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\-11y+11z=-11\end{array}\right.\Rightarrow \left\{\begin{array}{l}3x+2y+3z=3\\23y-9z=9\\y-z=1\end{array}\right.$

Multiply the third equation by 23 and subtract it from the second equation:

$\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\23y-9z-23(y-z)=9-23\cdot 1\end{array}\right.\Rightarrow \left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\23y-9z-23y+23z=9-23 \end{array}\right.$

Hence,

$\left\{\begin{array}{rl}3x+2y+3z=3\\23y-9z=9\\14z=-14 \end{array}\right.\Rightarrow z=-1$

Substitute it into the second equation:

$23y-9\cdot (-1)=9\Rightarrow 23y+9=9\\ \\23y=0\\ \\y=0$

Substitute them into the first equation:

$3x+2\cdot 0+3\cdot (-1)=3\Rightarrow 3x-3=3\\ \\3x=6\\ \\x=2$

The solution is $x=2,\ y=0,\ z=-1.$

3 0

3 years ago