3 years ago

From 1000, create a pattern by subtracting 8 from each number and stop at 5 numbers

Mathematics

1 answer:

shusha [124]3 years ago

7 0

Well subtract 8 from 1000 and then do that five times. so 992,984,976,968, and 960

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As we need to determine the value of k that will give one solution, set the discriminant to zero.

Given equation:

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$\begin{aligned}b^2-4ac & = 0\\\implies (-4)^2-4(k)(4) & = 0\\16-16k & = 0\\16k & = 16\\\implies k & = 1\end{aligned}$

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