F(x) = 2x + 5

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Find f(x + 1) :
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f(x +1) = 2(x + 1) + 5
f(x +1) = 2x + 2 + 5
f(x + 1) = 2x + 5

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Find -2f(x+1):
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-2(fx+1) = -2(2x + 5)
-2(fx+1) = -4x - 10

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Answer: -2(fx+1) = -4x - 10
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3 0

3 years ago

What's 10 3/4 - 7 1/4?

leva [86]

$10 \frac{3}{4} - 7 \frac{1}{4} \\ \\ \frac{10 \times 4 + 3}{4} -7 \frac{1}{4} \\ \\ \frac{43}{4} - y \frac{1}{4} \\ \\ \frac{43}{4} - \frac{7 \times 4 + 1}{4} \\ \\ \frac{43}{4} - \frac{29}{4} \\ \\ \frac{43-29}{4} \\ \\ \frac{14}{4} \\ \\ \frac{7}{2} \\ \\ 3 \frac{1}{2} \\ \\ Answer: \fbox {3 \ 1/2} \ or \ \fbox {3.5}$

5 0

3 years ago

25. Michael is studying population changes in two

g100num [7]

Answer: Average rates of change for Bird A is 0.045 and for Bird B is 3.816.

Step-by-step explanation: Through its graph, a function can be analyzed and be identified its attributes. Average Rate of Change is the ratio of change in the function values to the change of x-value, i.e., it is the slope of the function in a specific interval of x. With the Average it is possible to compare two function.

Average Rate of Change

Bird A:

For the interval [0,18]:

x₁ = 0 f(0) = 8.3

x₂ = 18 f(18) = 9.1

Average = $\frac{f(18) - f(0)}{x_{2} - x_{1} }$

Average = $\frac{9.1 - 8.3}{18 - 0}$

Average = 0.045

Bird B: y = 3.6(1.06)x

For the interval [0,18]:

x₁ = 0 y = 3.6(1.06)0 = 0

x₂ = 18 y = 3.6(1.06)18 = 68.7

Average = $\frac{f(18) - f(0)}{x_{2} - x_{1} }$

Average = $\frac{68.7 - 0}{18 - 0}$

Average = 3.816

The Average Rate for Change for Bird A is 0.045 and for Bird B is 3.816. This means that the population of Bird B increase in rate faster than the population of Bird A.

4 0

3 years ago