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djverab [1.8K]
3 years ago
12

Solve (x + 9)2 = 25.

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0

Answer:

x = -4 and x = -14

Step-by-step explanation:

Our equation is (x + 9)² = 25

Applying the square root property we would need to take the square root of both sides: \sqrt{(x+9)^{2} } =\sqrt{25}

This give us x + 9 = ±5

Here we have two equations since taking the square root gives us a positive and negative value

Our first equation is x + 9 = 5, and to isolate the variable we would need to subtract 9 from both sides, giving us x = -4

Our second equation is x + 9 = -5, and to isolate the variable we would need to subtract 9 from both sides, giving us x = -14

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Corrected Question

a. Develop a probability distribution for the job satisfaction score of a senior executive.

b. Develop a probability distribution for the job satisfaction score of a middle manager.

c. What is the probability a senior executive will report a job satisfaction score of 4 or 5?

d. What is the probability a middle manager is very satisfied?

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(d)0.28

Step-by-step explanation:

The percent frequency distributions of job satisfaction scores os give below:

\left|\begin{array}{c|c|c}$Job Satisfaction Score&$IS Senior Executives(\%)&$IS Middle Managers(\%)\\1&5&4\\2&9&10\\3&3&12\\4&42&46\\5&41&28\end{array}\right|

(a)Probability distribution for the job satisfaction score of a senior executive.

\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_1(x))\\------&------\\1&0.05\\2&0.09\\3&0.03\\4&0.42\\5&0.41\end{array}\right|

(b)Probability distribution for the job satisfaction score of a middle manager.

\left|\begin{array}{c|c}$Job Satisfaction Score&$Relative Frequency (f_2(x))\\1&0.04\\2&0.10\\3&0.12\\4&0.46\\5&0.28\end{array}\right|

(c)Probability a senior executive will report a job satisfaction score of 4 or 5

P(a senior executive will report a job satisfaction score of 4 or 5)

=f_1(4)+f_1(5)\\=0.42+0.41\\=0.83

(d)Probability a middle manager is very satisfied

The probability a middle manager is very satisfied

=f_2(5)\\=0.28

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