The greatest GCF would be
Answer:
$10 coins: 21
$20 coins: 24
Step-by-step explanation:
heyy me again
So we can create 2 equations where
x = number of $10 coins
y = number of $20 coins:
x + y = 45
10x + 20y = 690
we can move equation 1 around so that we can get a value of x
x = 45 - y
now we can substitute x into the second equation
10(45 - y) + 20y = 690
450 - 10y + 20y = 690
10y = 240
y = 24
Now plug in y back into the first equation
x = 45 - y
x = 45 - 24
x = 21
22.4
If the bottom side is 20 cm, then each line BE and CE would each be 10 cm.
Now, just focus on the top left triangle. You have one side with 20 cm, and the other side with 10 cm. You are left with the hypotenuse, which you need to figure out the value of.
Since this is a right triangle, you can use the Pythagorean theorem -> a^2 + b^2 = c^2 where c is the hypotenuse.
20^2 + 10^2 = c^2
400 + 100 = c^2
500 = c^2
22.36 = c
Answer:
Probability that Jonas gets an orange is 1/4 and Beth gets a peach is 3/16.
Step-by-step explanation:
Here,
The total number of fruits n(S) = 3 + 4 + 4 + 2 + 3
= 16
The total number of oranges n(O) = 4
The total number of peas n(P) = 3
Now,
P(O) = n(O)/n(S)
= 4/16
= 1/4
Again,
P(P)= n(P)/n(S)
= 3/16
Answer:
9
Step-by-step explanation:
