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stellarik [79]
2 years ago
7

Write the fraction 5/6 as a decimal

Mathematics
2 answers:
aliya0001 [1]2 years ago
8 0
5/6=
5÷6=0.833333333333333333 or about 0.83
zvonat [6]2 years ago
5 0

Answer:

5/6 = approximately 0.83

All you have to do is divide the numerator by the denominator.


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The operating costs for each machine for one day have an unknown distribution with mean 1610 and standard deviation 136 dollars.
BabaBlast [244]

Answer:

20.27

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

Using the Central Limit Theorem for Means, what is the standard deviation for the sample mean distribution?

This is s when \sigma = 136, n = 45. So

s = \frac{136}{\sqrt{45}} = 20.27

So the correct answer is:

20.27

3 0
2 years ago
Solve 7 ÷ one half = ___.<br> Question 1 options:<br><br> 14<br><br> 15<br><br> 24<br><br> 40
Norma-Jean [14]

Answer:

O 14

Step-by-step explanation:

hope it is helpful :)

7 0
2 years ago
Write down a multiple of 8 that is between 20 and 50.
serg [7]

Answer:

24, 32, 40, or 48

Step-by-step explanation:

Count by 8.

8

16

24

32

40

48

56

8 0
2 years ago
Read 2 more answers
What is the value of the expression? 1/6 + 1/6
Tems11 [23]
To get the  answer to this question simply add he numerators but keep the denominator the same which will give you 2/6 then you simplify the answer by 2/2 to get the simplified answer 1/3
7 0
3 years ago
Read 2 more answers
Find the area lying above the x-axis and below the parabolic curve y = 4x -x2 A. 8 B. 16 C. 10 2/3 D. 8 1/3
dimaraw [331]
To find the area between the x-axis and the parabolic curve, take the integral of the area in which the curve is above the x-axis.
function of the graph is
y = 4x - x²
We can tell by the function (specifically -x²) that the parabola will point downward.
To find the domain in which y>0, let's find the roots (0's) of the function:
0 = 4x - x²
0 = x (4 - x) 
x = 0 or x = 4
Between x=0 and x=4, the curve is above the x-axis. To find the area of the graph, let's take the integral on this range:

First, take the antiderivative of 4x - x²:
2x² - (1/3) x³
Then, plug x=4 into the anti-derivative, and subtract the anti-derivative at x=0:
2(4)² - (1/3)(4³) - (0 - 0)
32 - 64/3
96/3 - 64/3 = 32/3 

Closest Answer is C) 10
7 0
3 years ago
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