3 years ago

write the equation of the line that is perpendicular to the line y=-1/5x+9 and passes through the point (-2,-2)

1 answer:

4 0

Answer:y=5x+8

Step-by-step explanation: the perpendicular slope is going to be the negative reciprocal of your given slope. In this case the perpendicular line has a slope of 5, because u flip -1/5 to make -5 and u negate -5 to make 5. This perpendicular slope passes through (-2,-2) and u find the y intercept like this: -2=(5(-2))+b. Therefore the y intercept is 8 and the perpendicular slope is y=5x+8

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