The rectangle that has area 400 has width 10, so its length is 40.
A = LW; L = A/W = 400/10 = 40
The length is 10 + 0.2 = 10.2. The width is 10 + 2 = 12
The multiplication is 10.2 * 12
40.2 * 12 = 40 * 10 + 0.2 * 10 + 40 * 2 + 0.2 * 2
40.2 * 12 = 400 + 2 + 80 + 0.4
40.2 * 12 = 482.4
12 not sure if it's true or not.
Answer:
Area of rectangle = 225/2 or 112.5
Step-by-step explanation:
Given,
Consider a rectangle ABCD.
Let AC be a diagonal of rectangle of length = 15
In triangle ABC.
Sin 45° =height/hypotenuse {SinФ = height / hypotenuse}
Here, hypotenuse = diagonal of rectangle ( i.e AC = 15)
And height is AB
Therefore, sin 45° = AB/AC
or sin 45° = AB / 15
or 1/√2 = AB /15
AB = 15/√2
Similarly we can find Base (i.e BC) using cosine.
Cos 45° = Base/Hypotenuse
Cos 45° = BC / AC
or 1/√2 = BC/15
BC = 15/√2
Hence we got length of rectangle , AB= 15/√2
And width of rectangle , BC = 15/√2
Therefore, area of rectangle = Length × Width
Area of rectangle = 15/√2 × 15/√2 = 225/2
Hence, area of rectangle = 225/2 = 112.5
2. You simplified parenthesis on both sides
3. Subtracted 14 from -25 on right side
6. Divided each side by 9
