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AleksandrR [38]
4 years ago
6

If xy is rational, must either x or y be rational?

Mathematics
1 answer:
elena-s [515]4 years ago
8 0
Both x and y must be rational.
You might be interested in
Which function has a simplified base of 4 ^3 sqrt 4?
marusya05 [52]
We have
4^{3} * \sqrt{4}

We start by calculating square root:
4^{3} *2

We can rewrite 4 in base of 2:
( 2^{2}) ^{3}*2

Now we can calculate this by using rule of same base and different exponent:
2^{6}*2^{1} =2^{7} =128
5 0
3 years ago
Read 2 more answers
Which equation is the inverse of y = 9x2 - 4?
m_a_m_a [10]

Answer:

The inverse will be:

y' = \frac{\sqrt{x+4}}{3}

Step-by-step explanation:

In order to find the inverse of the equation, we do a variable change, since we are finding the inverse, :

f(x)  = 9x^{2} - 4

y = 9x^{2} - 4

x = 9y' ^{2} - 4

Now solve for y'.

First add 4 in both sides of the equation and change to the left y'.

x + 4= 9y'^{2} - 4+4

9y'^{2} = x + 4

Second divide by 9

9y'^{2}/9 = (x + 4)/9

y'^{2} = (x + 4)/9

Now you will have to clear y, with the square root.

[tex]y'^{\frac{2}{2}} = \sqrt{x + 4}  / \sqrt{9}[/tex] =

Simplifying terms

y' = \frac{\sqrt{x+4}}{3}

f^{-1}(x)  = \frac{\sqrt{x+4}}{3}

You can check the answer by doing the evaluation of the following equation:

(f o f^{-1} ) (x)

substitute the equation for y' or inverse function f^{-1}

f(\frac{\sqrt{x+4} }{3})

Now substitue the value into f(x)

You will have

= 9(\frac{\sqrt{x+4} }{3}} )^{2}  - 4\\\\Solving\\\\9(\frac{{x+4} }{9}} )  - 4

=x

5 0
3 years ago
Solve these 4 Answers and find the number of X
Stolb23 [73]

Answer:

5. x = -3

6. x = -2

7. x = 1/2

8. x = 9/5

Step-by-step explanation:

7 0
3 years ago
Allowance method entries
Feliz [49]

Using the Allowance Method, the relevant transactions can be completed in the books of Wild Trout Gallery as follows:

1. <u>Allowance for Doubtful Accounts</u>

Accounts                                          Debit       Credit

Jan. 1 Beginning balance                             $53,800

Jan. 19 Accounts Receivable                           2,560

Apr. 3 Accounts Receivable       $14,670

July 16 Accounts Receivable        19,725

Nov. 23 Accounts Receivable                         4,175

Dec. 31 Accounts Receivable       25,110

Dec. 31 Ending balance          $56,500

Dec. 31 Bad Debts Expenses                   $55,470

Totals                                        $116,005  $116,005

<u>Accounts Receivable</u>

Accounts                                          Debit               Credit

Jan. 1 Beginning balance           $2,290,000

Jan. 19 Allowance for Doubtful           2,560

Jan. 19 Cash                                                            $2,560

Apr. 3  Allowance for Doubtful                                14,670

July 16  Allowance for Doubtful                              19,725

July 16  Cash                                                             6,575

Nov. 23  Allowance for Doubtful         4,175

Nov. 23 Cash                                                             4,175

Dec. 31  Allowance for Doubtful                             25,110

Dec. 31   Sales Revenue            8,020,000

Dec. 31   Cash                                               $8,944,420

Dec. 31 Ending balance                                 $1,299,500

Totals                                        $10,316,735 $10,316,735

3. Expected net realizable value of the accounts receivable as of December 31 = $1,243,000 ($1,299,500 - $56,500)

Allowance for Doubtful Accounts ending balance = $40,100 ($8,020,000 x 0.5%)

<u>Allowance for Doubtful Accounts</u>

Accounts                                          Debit       Credit

Jan. 1 Beginning balance                             $53,800

Jan. 19 Accounts Receivable                           2,560

Apr. 3 Accounts Receivable       $14,670

July 16 Accounts Receivable        19,725

Nov. 23 Accounts Receivable                         4,175

Dec. 31 Accounts Receivable       25,110

Dec. 31 Ending balance           $40,100

Dec. 31 Bad Debts Expenses                  $39,070

Totals                                        $99,605   $99,605

4. a. Bad Debt Expense for the year = $39,070

4.b. Balance for Allowance Accounts = $40,100

4.c. Expected net realizable value of the accounts receivable = $1,259,400 ($1,299,500 - $40,100)

Data Analysis:

Jan. 19 Accounts Receivable $2,560 Allowance for Uncollectible Accounts $2,560

Jan. 19 Cash $2,560 Accounts Receivable $2,560

Apr. 3 Allowance for Uncollectible Accounts $14,670 Accounts Receivable $14,670

July 16 Cash $6,575 Allowance for Uncollectible Accounts $19,725 Accounts Receivable $26,300

Nov. 23 Accounts Receivable $4,175 Allowance for Uncollectible Accounts $4,175

Nov. 23 Cash $4,175 Accounts Receivable $4,175

Dec. 31 Allowance for Uncollectible Accounts $25,110 Accounts Receivable $25,110

Accounts Receivable ending balance = $1,299,500

Allowance for Uncollectible Accounts ending balance = $56,500

Learn more: brainly.com/question/22984282

4 0
3 years ago
A counter top is 18 feet long and 3 feet wide. What is the area of the counter top in square meters? Use the conversion 1 foot =
podryga [215]

Answer:

Area of the counter top is 5.02\ m^2.

Step-by-step explanation:

Given:

Length of the Counter top = 18 feet

Width of the counter top = 3 feet

We need to find the area of the counter top is square meter;

Solution:

Now we need to find the area of the counter top is square meter.

But given data is in feet so we will first convert feet into meters.

1 foot = 0.305 meter.

So 18 feet = Number of meters in 18 feet.

By Using Unitary method we get;

Number of meters in 18 feet = 18\times 0.305 = 5.49\ m

Length of the Counter top = 5.49 m

Also 3 feet = Number of meters in 3 feet.

Again Using Unitary method we get;

Number of meters in 3 feet = 3\times 0.305 = 0.915\ m

Width of the counter top = 0.915 m

Now we know that;

Area of the counter top can be calculated by multiplying Length of the counter top with width of the counter top.

framing in equation form we get;

Area of the counter top = 5.49\times 0.915 = 5.0233\ m^2

Rounding up to 2 decimals we get;

Area of the counter top =  5.02\ m^2

Hence Area of the counter top is 5.02\ m^2.

3 0
4 years ago
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