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gladu [14]
3 years ago
8

Flora made 7 withdrawals of 275

Mathematics
1 answer:
djyliett [7]3 years ago
4 0

Answer:

.......................

You might be interested in
Use integration by parts to find the integrals in Exercise.<br> ∫(x+6)ex dx.
skelet666 [1.2K]

Answer:

xe^x+5e^x

Step-by-step explanation:

We have given integral \int (x+6)e^xdx

\int (xe^x+6e^x)dx

\int (I_1+I_2)dx , here I_1=xe^x and I_2=6e^x

Now first integrate I_1

So I_1=\int xe^x

Integrating by part

I_1=x\int e^x-\int e^x\frac{d}{dx}x

I_1=x e^x- e^x

I_2=6\int e^x=6e^x

So I=I_1+I_2=xe^x-e^x+6e^x=xe^x+5e^x

5 0
3 years ago
Find a formula for the sum of the first n even positive integers.
melisa1 [442]
So even postive integers are by defention in form 2k where k is a natural number so
let the sum of even integers to n=S
S=2(1+2+3+4+5+6+7+8+......+k-1+k
divide bith sides of equation 1 by 2
0.5S=1+2+3+4+5+...........+k-1+k
S=2(k+(k-1)+..............................+2+1)
divide both sides of equation 2 by 2
0.5S=k+k-1+..............................+2+1)
by adding both we will get
___________________________
S=(k+1)(k)
so the sum will be equal to
S=
{k}^{2}  + k
so let us test the equation
for the first 3 even number there sums will be
2+4+6=12
by our equation 3^2+3=12
gave us the same answer so our equation is correct
7 0
2 years ago
Find the slope of the line passing through (-9,3), (-3,-5)
egoroff_w [7]

Answer:

-4/3

Step-by-step explanation:

Slope: (y2-y1)/(x2-x1)

(-5-3)/(-3+9) = -8/6 = -4/3

The slope is -4/3

6 0
3 years ago
The mass, m kilograms, of a horse is 429 kg, correct to the nearest kilogram.
Liula [17]

Answer:

400 < m< 430 kg

Step-by-step explanation:

the mass of horse is 429 kg

estimated to the nearest hundred is 400  kg

estimated to the nearest  tens is 430 kg

thus the value of m mass lies between 400 to 430

therefore

400 < m< 430 kg

6 0
1 year ago
Read 2 more answers
Determine the domain of the function h=9x/x(x^2-49)
Juliette [100K]

ANSWER

( -  \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , +   \infty )

EXPLANATION

The given function is

h(x) =  \frac{9x}{x( {x}^{2} - 49) }

This function is defined for values where the denominator is not equal to zero.

x( {x}^{2}  - 49) \ne0

x(x - 7)(x + 7) = 0

The domain is

x \ne - 7, x \ne0, \: and \:  x \ne 7,

Or

( -  \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , +   \infty )

8 0
3 years ago
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