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3 years ago

Flora made 7 withdrawals of 275

Mathematics

1 answer:

djyliett [7]3 years ago

4 0

Answer:

.......................

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2 Which graph shows a proportional relationship? a b c d

Harrizon [31]

Answer:

x xjjkdjbdnnxuhxnmdujxnxlxuxbx

6 0

2 years ago

HELP ASAP!! WILL GIVE 25 POINTS AND BRAINLIEST.

Luba_88 [7]

Answer:

As shown in picture,

Option 2 is correct.

Horizontal asymptote at y = 0 (graph approaches to 0 when x at -infinity and + infinity)

Option 4 is correct.

Vertical asymptote at x = 6 ( graph goes to infinity when x = 6)

Option 5 is correct.

Vertical asymptote at x = -4 ( graph goes to infinity when x = -4)

Hope this helps!

6 0

3 years ago

Read 2 more answers

Fill in the gaps in the arithmetic sequence -3, _ ,_ , _, _, _ 12

lord [1]

Answer:

-0.5, 2, 4.5, 7, 9.5

Step-by-step explanation:

The given terms are 6 apart, so the common difference is 1/6 of their difference:

d = (12 -(-3))/6 = 15/6 = 5/2 = 2.5

Add 2.5 to each term to get the next one. Then the sequence is ...

-3, -0.5, 2.0, 4.5, 7.0, 9.5, 12

8 0

3 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

3 years ago

It takes one week for a crew of workers to pave 3/5 kilometer of a road. At that rate, how long will it take to pave 1 kilometer

Flauer [41]

Answer:

1.67 weeks

Step-by-step explanation:

Let X= time it will take to pave 1 kilometer?

1 week=3/5 kilometer

X week =1 kilometer

Cross multiply

3/5 X= 1

3X= 5

X= 5/3

1.67 weeks

8 0

3 years ago