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goldenfox [79]
3 years ago
11

Hummingbirds drink nectar from flowers. As they pass from flower to flower,

Biology
1 answer:
notka56 [123]3 years ago
3 0
C. Mutualistic relationship

Flowers and hummingbirds have a mutualistic relationship where both benefit. Flowers produce food in the form of nectar (sugar and water) to attract hummingbirds which, in turn, move pollen for the plant (pollination).
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Almost no species ever reaches its biotic potential—the population size that the species could produce if all individuals surviv
velikii [3]

<span>Out of the following given choices;</span>

<span>A.    </span><span>symbiote.                                                                   C.  capacity limiter</span>

<span>B.      </span><span>producer.                                                                  D.  limiting factor

</span>

The answer is D. Limiting factors limit the ideal growth rate of a population. Examples of these limiting factors include space (low space) and food (scarce food). These limiting factors would limit the population growth rate either by causing emigration, increases birth rate, and decrease birth rate.

7 0
3 years ago
Read 2 more answers
7.Write the structure and function of Endoplasmic Reticulum and golgibodies? pls pls answer it fast ...
Papessa [141]

Answer:

Endoplasmic Reticulum

Structure

It is a large dynamic structure that serves many role in the cell including calcium storage, lipid metabolism, etc.

Function

It's function is to produce protein for the rest of cells to function.

Golgi bodies

Structure

It is made up of series of flattened stacked pouches

Function

It collect and distribute substance made in cell,synthesis and secretion of many material.

4 0
2 years ago
If someone did not meet the recommended intake of fat-soluble vitamins for one day, you would tell him to
Mars2501 [29]
Not to be concerned as long as the diet as a whole provides average amounts 
4 0
3 years ago
assume that life on Mars requires cell potential to be 100mV, and the extracellular concentrations of the three major species ar
svetlana [45]

Answer:

Explanation:

From the information given:

The cell potential on mars E = + 100 mV

By using Goldman's equation:

E_m = \dfrac{RT}{zF}In \Big (\dfrac{P_K[K^+]_{out}+P_{Na}[Na^+]_{out}+P_{Cl}[Cl^-]_{out} }{P_K[K^+]_{in}+P_{Na}[Na^+]_{in}+ P_{Cl}[Cl^-]_{in}}      \Big )

Let's take a look at the impermeable cell with respect to two species;

and the two species be Na⁺ and Cl⁻

E_m = \dfrac{RT}{zF} In \dfrac{[K^+]_{out}}{[K^+]_{in}}

where;

z = ionic charge on the species = + 1

F = faraday constant

∴

100 \times 10^{-3} = \Big (\dfrac{8.314 \times 298}{1\times 96485} \Big) \mathtt{In}  \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

3.981= \mathtt{In} \Big ( \dfrac{4}{[K^+]_{in}}   \Big)

exp ( 3.981) = \dfrac{4}{[K^+]_{in}} \\ \\  53.57 = \dfrac{4}{[K^+]_{in}}

[K^+]_{in} = \dfrac{4}{53.57}

[K^+]_{in}  = 0.0476

For [Cl⁻]:

100 \times 10^{-3} = -0.0257 \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

-3.981 =  \  \mathtt{In} \Big ( \dfrac{120}{[Cl^-]_{in}}   \Big)

0.01867 =  \dfrac{120}{[Cl^-]_{in}}

[Cl^-]_{in} = \dfrac{120}{0.01867}

[Cl^-]_{in} =6427.4

For [Na⁺]:

100 \times 10^{-3} = 0.0257 \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

53.57= \Big ( \dfrac{145}{[Na^+]_{in}}   \Big)

[Na^+]_{in}= 2.70

6 0
2 years ago
Number 3 and 4 Please! <br><br> Thanks in advance...
Ganezh [65]
What grade are you in if you are in 5th or 6th i can help you

5 0
2 years ago
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