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skad [1K]
3 years ago
5

Which type of cell division causes a puppy to grow into an adult dog?

Biology
2 answers:
Katen [24]3 years ago
5 0
Answer is mitosis

Meiosis is for sexual reproduction and for producing offspring, whereas mitosis is the cell division for cell reproduction so it has to be mitosis as it is the cause of cell growth, allowing the puppy to grow into an adult dog

It wouldn't be eukaryotic or homeostasis since they're not types of cell division.
goblinko [34]3 years ago
4 0
Meiosis is the answer :)
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The gametophyte is green and nutritionally independent in
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Answer:

The gametophyte is green and nutritionally independent in mosses, liverworts, and fern.

Explanation:

The gametophyte is the sexual stage of growth in plants and algae.

During this stage, there is production of reproductive organs which produce sex cells.

During this stage, the gametophyte is independent since it relies fully on itself for food production.

The presence of chlorophyll enables this independence.

The gametophyte produces its own food through photosynthesis.

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One human impact on the phosphorus cycle occurs through:
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2 years ago
A farmer crosses a purple-flowered pea plant with a white-flowered pea plant and plants the seeds. The farmer observes that all
Musya8 [376]

Note about the question:

Probably there are options for this question, but I failed in finding them. However, in the explanation box I will explain the reason for the lack of white flowers in the F1.

Answer:

The purple phenotype is dominant over the white phenotype. The allele that expresses the purple color is dominant and, in a heterozygous state, hides the expression of the recessive allele that expresses the white color. Principle of dominance.

Explanation:

Due to technical problems, you will find the complete explanation in the attached files.

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6 0
2 years ago
In a hypothetical population of 2500 people, 2275 people have brown eyes and 225 people have blue eyes (the homozygous-recessive
aev [14]

Answer:

In the next generation of 4000 children, 1680 of them will be heterozygous for the eye colour.

Explanation:

There's a population of 2500, 2275 of with have brown eyes and 225 blue eyes. <u>Let's call the dominant allele associated with brown colour "B" and the recessive allele associated with blue colour "b"</u>. So the possible genotypes are BB, Bb and bb, being BB and Bb brown eyed individuals and bb blue eyed individuals.

If the population it's in Hardy-Weinberg equilibrium, it means genotypic and allelic frequencies don't change from one generation to the following.

From the information given, we can calculate both allelic and genotypic frequencies.

First, we know that the frequency of the genotype bb it's the amount of blue eyed individuals over the total population.

  • f(bb)=225/2500=0.09

Additionally we know the allelic frequencies can be related to the genotypic ones when the population it's in Hardy-Weinberg equilibrium. Particularly we can say:

  • f(bb)=[f(b)]^2 => f(b)=[f(bb)]^(1/2)= 0.3 <em>(square root of f(bb)).</em>

Also, we can calculate the frequency of the B allele, as the probability of all alleles of the gene sum 1. In other words:

f(b)+f(B)=1 => f(B)=1 - f(b) = 1 - 0.3 = 0.7

So far, we have calculated the allelic frequencies, f(b)=0.3 and f(B)=0.7.

Now we can calculate the genotypic frequencies, using the equations of the Hardy-Weinberg equilibrium.

  • f(bb)=[f(b)]^2 => f(bb)=0.3^2=0.09
  • f(Bb)=2*f(B)*f(b) => f(Bb)=2*0.7*03=0.42
  • f(BB)=[f(B)]^2 => f(BB)=0.7^2=0.49

Finally, knowing that there are 4000 children in the next generation, to know how many of them are expected to be heterozygous for the eye colour, we should multiply the number of children for the probability of being heterozygous for the eye colour (which is the genotypic frequency for the genotype Bb).

  • Nº of heterozygous individuals = f(Bb)*total population= 0.42*4000
  • => Nº of heterozygous individuals =1680

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3 0
3 years ago
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Nezavi [6.7K]

<u>Answer:</u>

Neutrophils, eosinophils, and basophils are called <u>GRANULOCYTES</u> because they have prominent cytoplasmic inclusions that, in a stained blood smear, appear with identifying, characteristic colors.

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2 years ago
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