Answer:
5x + 6y = 20_____(1)
8x - 6y = -46_____(2)
Solving simultaneously:
Eqn(1) + Eqn(2)
5x + 8x + 6y + (-6y) = 20 + (-46)
13x = -26
x = -2
substituting this into Eqn (1):
5(-2) + 6y = 20
-10 + 6y = 20
6y = 30
y = 5
hence:
x = -2,y = 5.
In this current scenario,
Probability of passing, p = 65% = 0.65
Then,
Probability of not passing, q = 1-p = 1-0.65 = 0.35
Part (a): When 15 people are tested
(i) Number of people expected to pass
This is 65% of the 15 people tested. That is,
Number of people expected to pass = 0.65*15 = 9.75. This is rounded downwards as upward rounding will violate the 65% criteria.
Therefore,
Number of people expected to pass = 9 people.
(ii) Probability that 11 people are expected to pass the test
p(x=11) = [15Cx]*p^x*q^(15-x) = [15C11]*0.65^11*0.35^(15-11) = 0.1792 ≈ 17.92%
Part (b): Teenager determined to pass the test no matter how many times
(i) Probability that he passes the test the third time
This means that he will fail the first and second time. That is,
Probability pf passing the third time = q*q*p = 0.35*0.35*0.65 = 0.079625 = 7.9625%
(ii) Number of trials it takes to pass
This is a case of mathematical expected, E, that it takes before first occurrence of success. Normally,
E = 1/p
Substituting;
E = 1/0.65 = 1.54 ≈ 2
Therefore, at least two trials will be required.
The perpendicular bisector is a line segment that is drawn from a vertex of an angle to the midpoint of another line segment creating a right triangle or a 90° angle in the process. Suppose AB is the base segment of the triangle, therefore the perpendicular sector is also the angle bisector of the other angle of the triangle, supposedly angle C. Angle bisector is a line segment that divides the angle into two equal parts. Imagine a line drawn from the top vertex C extended down to the midpoint of line AB. That is the perpendicular and angle bisector.
Answer:
height = 142.00 ft
height ≈ 200. 82 ft
height ≈ 245.95 ft
Step-by-step explanation:
The picture below represent the image of the draw bridge. The illustration will form a right angle triangle. The hypotenuse is each half of the drawbridge which is 284 ft long. The opposite side of the triangle is facing the drawbridge half leg and the adjacent side is horizontal length. This is the side that made the angle with the drawbridge half leg(hypotenuse).
The question ask us to find the height of the drawbridge when it rise which is the opposite sides of the triangle when the angle is 30° , 45° and 60°.
Using SOHCAHTOA principle,
Angle 30°
sin 30° = opposite/hypotenuse
sin 30° = height/284
cross multiply
height = 0.5 × 284
height = 142.00 ft
Angle 45°
sin 45° = height/284
height = 284 × 0.70710678118
height = 200.818325857
height ≈ 200. 82 ft
Angle 60°
sin 60 = height/284
cross multiply
height = 0.86602540378 × 284
height = 245.951214675
height ≈ 245.95 ft
