Ask question

Ask question

All categories

3 years ago

13

Answer please, thanks.

1 answer:

Rudik [331]3 years ago

4 0

A) The perimeter is the length around the rectangle, so it would be 2 + 5 + 2 + 5 = 14m

The area is 2m * 5m = 10m^2

b/c) You have to draw a rectangle with a perimeter of 14m, and an area that ISN'T 10m^2. You could draw a 3m by 4m rectangle which would have a perimeter of 14m and an area of 12m^2.

You might be interested in

Question Which sequence of transformations maps pre-image ABC to image A′B′C′ ? Triangle ABC was reflected over the y-axis and t

Stells [14]

The sequence of transformations was Triangle ABC was reflected over the y-axis and then translated 2 units up and 2 units to the right.

<h3>What is a transformation?</h3>

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, rotation and dilation.

Rigid transformation is the transformation that does not change the shape or size of a figure. Examples of rigid transformations are <em>translation, reflection and rotation</em>.

Find out more on transformation at: brainly.com/question/4289712

#SPJ1

7 0

2 years ago

A homogeneous rectangular lamina has constant area density ρ. Find the moment of inertia of the lamina about one corner

frozen [14]

Answer:

$I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

Step-by-step explanation:

By applying the concept of calculus;

the moment of inertia of the lamina about one corner $I_{corner}$ is:

$I_{corner} = \int\limits \int\limits_R (x^2+y^2) \rho d A \\ \\ I_{corner} = \int\limits^a_0\int\limits^b_0 \rho(x^2+y^2) dy dx$

where :

(a and b are the length and the breath of the rectangle respectively )

$I_{corner} = \rho \int\limits^a_0 {x^2y}+ \frac{y^3}{3} |^ {^ b}_{_0} \, dx$

$I_{corner} = \rho \int\limits^a_0 (bx^2 + \frac{b^3}{3})dx$

$I_{corner} = \rho [\frac{bx^3}{3}+ \frac{b^3x}{3}]^ {^ a} _{_0}$

$I_{corner} = \rho [\frac{a^3b}{3}+ \frac{ab^3}{3}]$

$I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

Thus; the moment of inertia of the lamina about one corner is $I_{corner} =\frac{\rho _{ab}}{3}(a^2+b^2)$

7 0

3 years ago

Natalie Jenny, Steve and Jatin paid $12 for their taxi. They shared this equally between them. What fraction did each pay?

algol [13]

Answer:

1/4

Step-by-step explanation:

12/4= 3

Each paid $3 but as a fraction 3/12=1/4

8 0

3 years ago

Read 2 more answers

Hit me up. Bet i snap back. Ianh_00

spin [16.1K]

Answer:

I dont have snap but i'm willing to talk...

Step-by-step explanation:

7 0

3 years ago

Use logarithmic differentiation to find the derivative of the function.y = x^8 sin(x)

givi [52]

$Answer: \frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})$

Step-by-step explanation:

Since we have given that

$y=x^{8sinx}$

By using logarithmic on both sides we get,

$log y= 8 sinx. logx$

(∵ $log(a^m)=m.loga$ )

Now, differentiating on both sides ,we get,

$\frac{1}{y}.\frac{\partial y}{\partial x}=8(\frac{\partial sinx}{\partial x}.logx+sinx \frac{\partial logx}{\partial x})$

$\\\frac{1}{y}\frac{\partial y}{\partial x}=8(cosx.logx+sinx.\frac{1}{x})$

$\\\frac{\partial y}{\partial y}=8y(cosx.logx+\frac{sinx}{x})\\\\\frac{\partial y}{\partial x}=8x^{8sinx}(cosx.logx+\frac{sinx}{x})$

6 0

3 years ago