X=0+y6x−5y=23
6x=23+5yx=23+5y6
now sub x=23+5y6in x=0+ywe get23+5y6=0+ymultiple both side of the equation by 6..we get23+5y=6ynow we solve for y..23=6y−5yy=23now since we find y...we can find x..by by substituting y=23 in the 1st or 2nd equation...so, using equation 1x=0+yx=0+23x=23
Hopefully this helps :)
Given:
Distance between two buildings = 
feet apart.
Distance between highway and one building = 
feet.
Distance between highway and second building = 
feet.
To find:
The standard form of the polynomial representing the width of the highway between the two building.
Solution:
We know that,
Width of the highway = Distance between two buildings - Distance of both buildings from highway.
Using the above formula, we get the polynomial for width (W) of the highway.
Combining like terms, we get
Therefore, the width point highway is 
.
Answer:
x=1
Step-by-step explanation:
So, first you make sure to multiply the parenthesis by the negative so then it would be,
-x-3=2x-6
Then you add the -3 from the right to the other side
so, -x=2x-3
Then you want all the X variables to one side so you subtract the 2x to both sides.
so, -3x=-3
divide both by -3
x=1
Answer:5
Step-by-step explanation:
f(4)= ((1/2)*4)+3= 2+3=5
