Select the two variables that are held constant when testing Boyle's law in a manometer.
2 answers:
<u>Answer:</u> The variables which remain constant while testing Boyle's law is temperature and number of moles.
<u>Explanation:</u>
Boyle's law states that pressure of the gas is inversely proportional to the volume of the gas at constant temperature and number of moles.
Mathematically,
(At constant temperature and number of moles)
or,
With increase in pressure, the volume of the gas decreases and vice-versa.
Hence, the variables which remain constant while testing Boyle's law is temperature and number of moles.
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Taking into account the reaction stoichiometry, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.
<h3>Reaction stoichiometry</h3>In first place, the balanced reaction is:
2 Bi + 3 Cl₂ → 2 BiCl₃
By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:
- Bi: 2 moles
- Cl₂: 3 moles
- BiCl₃: 2 moles
The molar mass of the compounds is:
- Bi: 209 g/mole
- Cl₂: 70.90 g/mole
- BiCl₃: 315.45 g/mole
Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:
Bi: 2 moles ×209 g/mole=418 g
Cl₂: 3 moles ×70.90 g/mole= 212.7 g
BiCl₃: 2 moles ×315.45 g/mole= 630.9 g
<h3>Mass of Cl₂ required</h3>The following rule of three can be applied: If by reaction stoichiometry 630.9 grams of BiCl₃ are formed by 212.7 grams of Cl₂, 3.32 grams of BiCl₃ are formed by how much mass of Cl₂?
<u><em>mass of Cl₂= 1.119 grams</em></u>
Finally, 1.119 grams of chlorine gas are required to produce 3.32 grams of bismuth chloride is produced.
Learn more about the reaction stoichiometry:
Answer:
cis 2,3-dibromo- 2-butene
trans 2,3-dibromo- 2-butene
Explanation:
The cis-trans or geometric isomerism is due to restricted rotation around a carbon-carbon bond. This restriction may be due to the presence of double bonds or cycles.
The carbon-carbon double bond prevents free rotation of atoms in molecules. These two molecules have the same atoms, but they are different molecules. They are geometric isomers to each other.
The given compound can exist in the form of two isomers, cis and trans. The isomer that has the substituents on the same side is called cis, and the one that has them on opposite sides is trans.
<h2>0.72 mol/L</h2>
Explanation:
We are given a solution which contains
of
.
To calculate number of moles of present, we need to find it's molar mass from charts. Molar Mass of
is known to be
.
Number of moles of present =
Molarity =
∴ Molarity of given solution =