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3 years ago

7

Helpp chemistry ..........

1 answer:

ValentinkaMS [17]3 years ago

3 0

Half-life is the time it takes for the radioactive material's mass to decrease by half.

So, half of 96 is 48
half of 48 is 24
half of 24 is 12
half of 12 is 6

96->48->24->12->6

You count how many arrows (->) there is.
Which is 4

Then you use the 12 minutes the question gave you to do:
12 divided by 4
= 3

So, one half-life (Or the time it takes for the radioactive material's mass to decrease in half) is 3 minutes

and every 3 minutes it will decrease by half.

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alukav5142 [94]

Answer:

will form bonds between atoms. for more details are in the pic

7 0

3 years ago

PLEASE HELP, I WILL GIVE BRAINLIEST AND THANKS

jasenka [17]

Answer:

23dm

Explanation:

so you have to do 10g +13dm so the you have to times it by 3 three times

3 0

3 years ago

How to convert n butylbenzene to benzoic acid

Pavlova-9 [17]

<u>Answer:</u>

<u>When an alkyl benzene is heated with strong oxidizing asgents like acidic or alkline KMnO4</u>

<u> or acidified K2Cr2O7</u>

<u>, etc. gives aromatic carboxyllic acid. The alkyl side chain gets oxidised to −COOH</u>

<u> group irrespective of the size of the chain.</u>

Explanation:

4 0

3 years ago

An unknown compound with a molar mass of 223.94 g/mol consists of 32.18% c, 4.50% h, and 63.32% cl. find the molecular formula f

Dima020 [189]

The actual number of atoms of each element present in the molecule of the compound is represented by the formula known as molecular formula.

Molar mass of the unknown compound = 223.94 g/mol (given)

Mass of each element present in the unknown compound is determined as:

Mass of carbon, $C$ :

$\frac{32.18}{100}\times 223.94 = 72.06 g$

Mass of hydrogen, $H$ :

$\frac{4.5}{100}\times 223.94 = 10.08 g$

Mass of chlorine, $Cl$ :

$\frac{63.32}{100}\times 223.94 = 141.79 g$

Now, the number of each element in the unknown compound is determined by the formula:

$number of moles = \frac{given mass}{molar mass}$

Number of moles of $C$ :

$number of moles = \frac{72.06}{12} = 6.005 mole\simeq 6 mole$

Number of moles of $H$ :

$number of moles = \frac{10.08}{1} = 10.08 mole\simeq 10 mole$

Number of moles of $Cl$

$number of moles = \frac{141.79}{35.5} = 3.99 mole\simeq 4 mole$

Dividing each mole with the smallest number of mole, to determine the empirical formula:

$C_{\frac{6}{4}}H_{\frac{10}{4}}Cl_{\frac{10}{4}}$

$C_{1.5}H_{2.5}Cl_{1}$

Multiplying with 2 to convert the numbers in formula into a whole number:

So, the empirical formula is $C_{3}H_{5}Cl_{2}$ .

Empirical mass = $12\times 3+1\times 5+2\times 35.5 = 112 g/mol$

In order to determine the molecular formula:

n = $\frac{molar mass}{empirical mass}$

n = $\frac{223.94}{112} = 1.99 \simeq 2$

So, the molecular formula is:

$2\times C_{3}H_{5}Cl_{2} = C_{6}H_{10}Cl_{4}$

6 0

3 years ago

which of the following compounds will likely have a bent triatomic structure? A. H2S. B. O2 C.NI3 D.CH4

Ymorist [56]

a) H2S is your answer.

5 0

3 years ago