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Taya2010 [7]
3 years ago
6

Which substances are made up of polymers?

Chemistry
2 answers:
cluponka [151]3 years ago
8 0
Polymer are made of rubber car tires
Tresset [83]3 years ago
7 0

The following are polymers

DNA : it is a polymer of nucleic acids

Protein in hair: it is a polymer of amino acids

rubber car tires: it is a polymer (it can be nylon or buna rubber etc)



ICE crystals : it is not a polymer,It is just a compound (water) in its solid phase

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A defibrillator delivers about 300 joules per shock calculate the number of calories
Tanya [424]

Answer:- 71.7 calories

Solution:- it is a unit conversion problem where we need to convert joules into calories.

The unit conversion for these energy units is:

1 calorie = 4.184 joule

The given energy is 300 joules and has to be converted to calories. We will show the set up using dimensional analysis.

300joules(\frac{1calorie}{4.184joules})

= 71.7 calories

So, the energy in calories is 71.7.


4 0
3 years ago
Calcium Oxide will react with ammonium chloride to produce ammonia gas, water vapor, and calcium chloride. If only 16.3 g of amm
Vaselesa [24]

Answer:

                     %age Yield  =  22.72 %

Explanation:

                    The balance chemical equation is as follow;

                           2 NH₄Cl + CaO → 2 NH₃ + CaCl₂ + H₂O

Step 1: <u>Calculate Moles of CaO, NH₄Cl and NH₃;</u>

CaO:

        Moles  =  Mass / M.Mass

        Moles  =  112 g / 56.07 g/mol

        Moles  =  1.99 moles of CaO

NH₄Cl:

        Moles  =  Mass / M.Mass

        Moles  =  224 g / 53.49 g/mol

        Moles  =  4.18 moles of NH₄Cl

NH₃:

        Moles  =  Mass / M.Mass

        Moles  =  16.3 g / 17.03 g/mol

        Moles  =  0.95 moles of NH₃

Step 2: <u>Calculate Limiting reagent as:</u>

According to equation.

                   2 moles of NH₄Cl reacts with  =  1 mole of CaO

So,

              4.18 moles of NH₄Cl will react with  =  X moles of CaO

Solving for X,

                     X =  4.18 mol × 1 mol / 2 mol

                     X  =  2.09 mol of CaO

This means that none of the given reagent is limiting reagent. They both are almost equal in number of moles.

Step 3: <u>Calculate Theoretical Yield of NH₃ as;</u>

According to equation.

                   2 moles of NH₄Cl produced  =  2 moles of NH₃

So,

              4.18 moles of NH₄Cl will produce  =  X moles of NH₃

Solving for X,

                     X =  4.18 mol × 2 mol / 2 mol

                     X  =  4.18 mol of NH₃

Step 4: <u>Calculate Percentage Yield as;</u>

             %age Yield  =  Actual Yield / Theoretical Yield × 100

             %age Yield  =  0.95 mol / 4.18 × 100

             %age Yield  =  22.72 %

5 0
3 years ago
Solid cesium bromide has the same kind of crystal structure as CsCl which is pictured below: If the edge length of the unit cell
Oxana [17]

Answer:

\mathbf {density \ d  =4.4845 \ g/cm^3}

Explanation:

Let recall the crystal structure of CsBr obtains a BCC structure. In a BCC structure, there exist only two atom per cell.

The density d of CsBr in g/cm³ can be calculated by using the formula:

\mathtt{ density \ d  = \dfrac{z \times molar\  mass  \ (M)}{ edge \ length \ (a)  \ \times avogadro's \ number \ (N)}}

where;

z = 1 mole of CsBr

edge length = 428.7 pm = (4.287 × 10⁻⁸)³ cm

molar mass of CsBr = 212.81 g/mol

avogadro's number = 6.023 × 10²³

\mathtt{ density \ d  = \dfrac{1 \times 212.81}{(4.287 \times 10^{-8})^3 \times 6.023 \times 10^{23}}}

\mathtt{ density \ d  = \dfrac{ 212.81}{47.4540533}}

\mathbf {density \ d  =4.4845 \ g/cm^3}

5 0
3 years ago
Name the four types of friction. Provide one example not used in your lesson for each type.
Bond [772]
Friction is the force that opposes motion between any surfaces that are in contact. There are four types of friction: static, sliding, rolling, and fluid friction. Static, sliding, and rolling friction occur between solid surfaces.
5 0
3 years ago
Calculate the mass percent of HOCH 2CH 2OH in a solution made by dissolving 3.2 g of HOCH 2CH 2OH in 43.5g of water.
grin007 [14]

Answer:

\%m/m=6.85\%

Explanation:

Hello,

In this case, we are asked to compute the by mass percent for the given 3.2 g of ethylene glycol in 43.5 g of water. In such a way, since the by mass percent is computed as follows:

\%m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%

Whereas the solute is the ethylene glycol and the solvent the water, therefore we obtain:

\%m/m=\frac{3.2g}{3.2g+43.5g} *100\%\\\\\%m/m=6.85\%

Best regards.

5 0
3 years ago
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