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3 years ago

HELP ME PLZ I don't get math

Mathematics

2 answers:

astra-53 [7]3 years ago

8 0

Answer:

y = 1.00+0.10 x

Step-by-step explanation:

Considering there is a minimum charge of $1 up until they reach the point of 1/10 mile you would adds 0.10 for every additional 1/10 mile.

So if you were to say y was the charges and x is the no of 1/10 miles then the equation for y in terms of x would be:

y =1.00 +1/10(x)

y = 1.00+0.10 x

Then you just plug everything in. Hope this helped! :)

Finger [1]3 years ago

7 0

Answer:

9/10 would be $1.80

2 would be $2.90

3 and 1/10 would be $4

10 would be $10.90

Step-by-step explanation:

Youre welcome bud im not sure how to explain tho

You might be interested in

The general solution of 2 y ln(x)y' = (y^2 + 4)/x is

Sav [38]

Replace $y'$ with $\dfrac{\mathrm dy}{\mathrm dx}$ to see that this ODE is separable:

$2y\ln x\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{y^2+4}x\implies\dfrac{2y}{y^2+4}\,\mathrm dy=\dfrac{\mathrm dx}{x\ln x}$

Integrate both sides; on the left, set $u=y^2+4$ so that $\mathrm du=2y\,\mathrm dy$ ; on the right, set $v=\ln x$ so that $\mathrm dv=\dfrac{\mathrm dx}x$ . Then

$\displaystyle\int\frac{2y}{y^2+4}\,\mathrm dy=\int\dfrac{\mathrm dx}{x\ln x}\iff\int\frac{\mathrm du}u=\int\dfrac{\mathrm dv}v$

$\implies\ln|u|=\ln|v|+C$

$\implies\ln(y^2+4)=\ln|\ln x|+C$

$\implies y^2+4=e^{\ln|\ln x|+C}$

$\implies y^2=C|\ln x|-4$

$\implies y=\pm\sqrt{C|\ln x|-4}$

4 0

3 years ago

Show work/pls explain

Tamiku [17]

9+6(2^2+4)
9+6(4+4)
9+(6)(8)
9+48
=57

5 0

3 years ago

HELPPPPPP ); WILL GIVE BRAINLIST.

Black_prince [1.1K]

<h3>Answer:</h3>

f(1) = 2
No. The remainder was not 0.

<h3>Explanation:</h3>

Synthetic division is quick and not difficult to learn. The number in the upper left box is the value of x you're evaluating the function for (1). The remaining numbers across the top are the coefficients of the polynomial in decreasing order by power (the way they are written in standard form). The number at lower left is the same as the number immediately above it—the leading coefficient of the polynomial.

Each number in the middle row is the product of the x-value (the number at upper left) and the number in the bottom row just to its left. The number in the bottom row is the sum of the two numbers above it.

So, the number below -4 is the product of x (1) and 1 (the leading coefficient). That 1 is added to -4 to give -3 on the bottom row. Then that is multiplied by 1 (x, at upper left) and written in the next column of the middle row. This proceeds until you run out of numbers.

The last number, at lower right, is the "remainder", also the value of f(x). Here, it is 2 (not 0) for x=1, so f(1) = 2.