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3 years ago

An angle measures 36° less than the measure of a complementary angle. What is the measure of each angle?

Mathematics

1 answer:

lutik1710 [3]3 years ago

6 0

Answer:

The answer is 64 and 26

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f a rectangle has a perimeter of 70, a length of x and a width of x - 9, find the value of the length of the rectangle.

trasher [3.6K]

$( x + (x - 9)) \times 2 = 70 \\( 2x - 9) \times2= 70 \\ 4x - 18 = 70 \\ 4x = 70 + 18 = 88$
$x = \frac{88}{4} = 22$
the length is 22

and the width is
22-9=17

good luck

3 0

3 years ago

Please answer these questions quick thank you!

BabaBlast [244]

Answer:

Step-by-step explanation:

8 0

2 years ago

There are white, blue, and red boats in a marina. Three-fourths of the boats in the marina are white, 4/7 of the remaining boats

insens350 [35]

Answer:

There are 84 total boats.

Step-by-step explanation:

In order to find this, we first need to find the fraction which are red. We can do this by multiplying the whole by how many are not white.

1 * 1/4 = 1/4

Now we take that amount and multiply it by the amount that are not blue of the remaining.

1/4 * 3/7 = 3/28

Now that we have this, and we know this is 9 boats, we can divide 9 by this fraction and it will give us the total number of boats.

9 ÷ 3/28 = 84

8 0

3 years ago

Use the following image to assist in your answer. a = - 6 - 9 - 4

vfiekz [6]

Step-by-step explanation:

Pythagoras' theorem for the smallest one :

$c^2 = 4^2 + 6^2$

$c^2 = 16 + 36$

$c^{2}$ = 52

Pythagoras' theorem for the middle one :

$b^{2}$ = $6^{2}$ + $a^{2}$

Pythagoras' theorem for the biggest one :

$(4+a)^2 = c^2 + b^2$

$16 + 8a + a^2 = 52 + b^2$

Using the formula before (for $b^2$ ) it becomes :

$16 + 8a + a^2 = 52 + (6^2 + a^2)$

$16 + 8a + a^2 = 52 + 6^2 + a^2$

$16 + 8a = 52 + 6^2$

16 + 8a = 52 + 36

16+8a = 88

8a = 88-16

8a = 72

$a = \frac{72}{8}$

a = 9

Verifying :

$b^2 = 6^2 + a^2$

$b^2 = 36 + 81$

$b^2 = 117$

$b^{2}$ = 117

The biggest one :

$(4+a)^2 = c^2 + b^2$

$(4+9)^2 = 52 + 117$

$13^2 = 169$

True

8 0

2 years ago

Write the quadratic equation whose roots are −6 and 2 , and whose leading coefficient is 5 . (use the letter x to represent the

White raven [17]

Here let the quadratic equation be ax^2 + bx + c We know that a=5 from the question. Since the roots are 6 and 2, the quadratic equation would take the form of a product like (a1x-b1)(a2x-b2). However, let's assume that a2=1 and b2=6, Since a=5, a1=5, then 5x-b1=5(x-2). Solving this shows that b1=10 So, the equation is (5x-10)(x-6)

3 0

3 years ago