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Mumz [18]
2 years ago
12

3. Tom was using wire of the following thicknesses 0.33 mm, 0.275 mm, 0.25 mm, and 0.3 mm for some electrical work. Order the wi

re from thickest to thinnest.
Mathematics
1 answer:
MA_775_DIABLO [31]2 years ago
8 0
0.33mm
0.3mm
0.275 mm
0.25mm
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-5x + 10y =40<br> Solve intercept form
Tema [17]
I thought I knew the answer but I don’t Srry I need points
5 0
2 years ago
im a senior trying to graduate my school has me in the wrong classes i have adhd and i was supposed to be in diffrent classes bu
CaHeK987 [17]

Step-by-step explanation:

hope you can send the questions again because your question is to long to answer everything. I answered 1,2,3,4

8 0
2 years ago
(Hehe...Please ignore the markings)
inysia [295]

Answer:

See below:

Step-by-step explanation:

Problem 1:

Multiply Equation 1 by 4, keep Equation 2 the same.

x+y=8, multiply each term by 4:

4*x=4x, 4*y=4y, 8*4=32

so, the equivalent system is: 4x+4y=32 and x-y=2

Solve the system of equations:

x-y=2 becomes x=y+2

plug into 4x+4y=32 to solve for y

4(y+2)+4y=32---> 4y+8+4y=32--->8y=24---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 1 Answer:

Equivalent system: 4x+4y=32, x-y=2; solution: x=5, y=3

Problem 2:

Keep Equation 1 the same. Add 1 and 2.

To add an equation, add the left sides together, and then the rights.

so: x+y=8 + x-y=2 gives us: 2x=10

solve for x ---> 2x/2=10/2--->x=5

plug x into x+y=8--->5+y=8--->y=3

Problem 2 answer:

Equivalent system: x+y=8, 2x=10; solution:x=5, y=3

Problem 3:

Subtract Equation 2 from 1, and keep 2 the same.

To subtract an equation, subtract the left sides, then the rights. We are subtracting 1<em> from </em>2, so its 2-1.

x-y=2 - x+y=8 gives us: -2y=-6

Solve for y by dividing by -2-->-2y/-2=-6/-2---> y=3

Plug into x-y=2---> x-3=2---> x=5

Problem 3 answer:

Equivalent system: -2y=-6, x-y=2; solution: x=5, y=3

Problem 4:

Multiply the sum of Equation 1 and 2 by a factor of 3. Keep equation 2 the same.

First we add 1 and 2: (we did this earlier) ---> 2x=10 ---> now we multiply it all by 3---> 2x*(3)=10*(3)---> this gives us: 6x=30---> now divide by 6 to solve for x: 6x/6=30/6 gives us: x=5

Now, solve for y by plugging x into equation 2: x-y=2---> 5-y=2--->y=3

Problem 4 answer:

Equivalent system: 6x=30, x-y=2; solution: x=5, y=3

______

Quick Tip: One thing inherent of Equivalent systems is that they have the same set of solutions. Thus, we know the systems are equivalent when they have the same set of solutions for x and y. Moreover, you don't need to solve every time after you attempt to find an equivalent system, instead, just plug in the values found in problem 1 to each new set of equations to test if they are equivalent.

If we find x=5 and y=3 for x+y=8 and x-y=2, then all we have to do is plug them in to 6x=30 and -2y=-6 to see if they are equivalent.

6(5)=30 ---> true

-2(3)=-6 ---> true

3 0
2 years ago
An item on sale cost 35% of the original price of The original price.the original price was $17
VMariaS [17]

First multiply 17 by the percentage:

17 x .35= 5.95

Then subtract that answer from 17:

17 - 5.95= 11.05

35% of 17 is 11.05


5 0
2 years ago
If the expression 3x+10 is equal to 6 for some value of x, then what is the value of 3x+2 equal to for the same value of x ?
Murrr4er [49]

Answer:

149

Step-by-step explanation:

If the expression 3x+10 is equal to 6 for some value of x, then what is the value of 3x+2 equal to for the same value of x ?

8 0
3 years ago
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