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2 years ago

12

3. Tom was using wire of the following thicknesses 0.33 mm, 0.275 mm, 0.25 mm, and 0.3 mm for some electrical work. Order the wi

re from thickest to thinnest.

1 answer:

MA_775_DIABLO [31]2 years ago

8 0

0.33mm
0.3mm
0.275 mm
0.25mm

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B2+4 <br> when b =3<br><br> help me please !!!!

Vadim26 [7]

Answer:

10

Step-by-step explanation:

P.s. Coefficient always goes before the variable

= 2b + 4

= 2(3) + 4 Substitute b for 3

= 6 + 4

= 10

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1 year ago

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The coffee pub has cans of coffee that weigh 4 4/5 pounds each. The pub has 8 1/2 cans of coffee left. What is the total weight?

tankabanditka [31]

4.8 x 8.5 = 40.8 lbs total
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2 years ago

Pls help I don’t understand this

Thepotemich [5.8K]

20% I think I’m sorry

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2 years ago

How many solutions are possible for a system of equations containing exactly one linear and one quadratic equation? (Select all

galina1969 [7]

Remember that a quadratic equation is a parabola. The equation is of the type y = Ax^2 + Bx + C

A linear equation is a straight line. The equation is of the type y = MX + N

The soluction of that system is Ax^2 + Bx + C = MX + N

=> Ax^2 + (B-M)x + (C-N) = 0

That is a quadratic equation.

A quadratic equation may have 0, 1 or 2 real solutions. Those are all the possibilitis.

So you must select 0, 1 and 2.

You can also get to that conclusion if you draw a parabola and figure out now many point of it you can intersect with a straight line.

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6 0

3 years ago

12What mistake did the student make when solvingtheir two-step equation?(a)b) If correctly solved what should the value of be?

mixas84 [53]

Given the equation:

$\frac{x}{6}+3=-18$

(a) You can identify that the student applied the Subtraction Property of Equality by subtraction 3 from both sides of the equation:

$\frac{x}{6}+3-(3)=-18-(3)$

However, the student made a mistake when adding the numbers on the right side.

Since you have two numbers with the same sign on the right side of the equation, you must add them, not subtract them and use the same sign in the result. Then, the steps to add them are:

- Add their Absolute values (their values without the negative sign).

- Write the sum with the negative sign.

Then:

$\frac{x}{6}=-21$

(b) The correct procedure is:

1. Apply the Subtraction Property of Equality by subtracting 3 from both sides (as you did in the previous part):

$\begin{gathered} \frac{x}{6}+3-(3)=-18-(3) \\ \\ \frac{x}{6}=-21 \end{gathered}$

2. Apply the Multiplication Property of Equality by multiplying both sides of the equation by 6:

$\begin{gathered} (6)(\frac{x}{6})=(-21)(6) \\ \\ x=-126 \end{gathered}$

Hence, the answers are:

(a) The student made a mistake by adding the numbers -18 and -3:

$-18-3=-15\text{ (False)}$

(b) The value of "x" should be:

$x=-126$

4 0

11 months ago