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Elis [28]
2 years ago
10

Use pemdas (2 + 6) x 4 - 7 write 3 steps

Mathematics
2 answers:
4vir4ik [10]2 years ago
8 0

Answer:

25

Step-by-step explanation:

(2 + 6) x 4 -7

 8 x 4 - 7

    32-7

      25

Please give me brainliest. Have a good day. :)

Anastasy [175]2 years ago
5 0
2+6=8
8x4=32
32-7=25

your answer is 25
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Which expression is equivalent to<br> (5^-2)(5^-1)<br> A. -1/125<br> B. -1/5<br> C. 1/125<br> D. 1/5
n200080 [17]

Answer:

1/125

Step-by-step explanation:

(5^-2)(5^-1) = 5^-3=1/5^3=1/125

3 0
3 years ago
Determine wether the graphs of the given equations are parallel, perpindicular, or neither.
guapka [62]
I wrote answers in picture and I use Desmos app to solve this equations

7 0
2 years ago
Please help me thank you.
Alexxandr [17]

Answer:

B

Step-by-step explanation:

3      -4    |   2

0      -1     |   7

3/2    -2    |   1

R1/3 ----> R1  (divide Row 1 by 3)

1       -4/3    |  2/3

0        -1      |   7

3/2      -2     |   1

R3 - 3/2  R1 -------> R3 (multiply Row 1 by 3/2 and subtract it from Row 3)

1      -4/3    |   2/3

0       -1      |    7

0       0      |    0

R2 / -1 -------> R2 (Divide Row 2 by -1)

1      -4/3   |  2/3

0        1     |   -7

0        0    |   0

R1 + 4/3 R2 --------> R1 (Multiply Row 2 by 4/3 and add it to Row 1)

1     0     |   -26/3

0    1      |      -7

0    0     |      0

5 0
3 years ago
What is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each ​
LenKa [72]

{\bold{\red{\huge{\mathbb{QUESTION}}}}}

what is the average cost of 7 articles if 3 of them cost 30k each and the rest cost 12.5k each

\bold{ \red{\star{\blue{GIVEN }}}}

TOTAL NUMBER OF ARTICLE= 7

ARTICLES FOR 30K = 3

ARTICLES FOR 12.5K = 7-3= 4

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

Average cost of 7 articles

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

\red{AVERAGE  =  \frac{TOTAL \:  COST}{ NUMBER  \: OF\: ARTICLES }}

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

Average \:  cost  \: of  \: 7  \: articles -  >  \\  \frac{(3 \times 30k) + (12 .5k \times 4)}{7}  \\  \frac{90k + 50k}{7}  \\  \frac{140k}{7}  \\  \blue {Average \:  cost  \: of  \: 7  \: articles -  >} \\ 20k

5 0
2 years ago
Can someone explain me how do i do (ii)?
Varvara68 [4.7K]

Answer:

(only ii right?)

Since we have the total number is 360° and our section is 72°, we know that the percentage of students who choose the cinema should be the number that we have divided to the total amount and then multiply the result by 100 ( it's fine if you write 100%, but when you actually calculate it, it's only 100, not 100%):

(72/360) . 100 = 20%

6 0
3 years ago
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