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ella [17]
3 years ago
10

Find two consecutive integers such that the sum of the first and twice the second is 74

Mathematics
2 answers:
givi [52]3 years ago
6 0
Let the consecutive integers be x and x+1
x+2(x+1)=74
or x+2x+2=74
3x=74-2=72
x=72/3=24
x+1=24+1=25
hence numbers are 24 and 25
timofeeve [1]3 years ago
6 0
Consecutive integers are 1 apart
they are x and x+1

sum of firt and  twice the 2nd is 74
sum is addition
twice is 2 times

x+2(x+1)=74
distribute
x+2x+2=74
add like terms
3x+2=74
minus 2 both sides
3x=72
divide both sides by 3
x=24
x+1=25

the numbers are 24 and 25
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Find the product of (5t-3) and (3t +7) when t = 6
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Answer:

675

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Step-by-step explanation:

<u>Step 1: Define</u>

(5t - 3) · (3t + 7)

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<u>Step 2: Evaluate</u>

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  2. (Parenthesis) Multiply:       (30 - 3) · (18 + 7)
  3. (Parenthesis) Subtract:      27 · (18 + 7)
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ozzi

Answer:

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