Find two consecutive integers such that the sum of the first and twice the second is 74

2 answers:

6 0

Let the consecutive integers be x and x+1
x+2(x+1)=74
or x+2x+2=74
3x=74-2=72
x=72/3=24
x+1=24+1=25
hence numbers are 24 and 25

timofeeve [1]2 years ago

6 0

Consecutive integers are 1 apart
they are x and x+1

sum of firt and twice the 2nd is 74
sum is addition
twice is 2 times

x+2(x+1)=74
distribute
x+2x+2=74
add like terms
3x+2=74
minus 2 both sides
3x=72
divide both sides by 3
x=24
x+1=25

the numbers are 24 and 25

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Step-by-step explanation:

The equation of a circle in standard form is ...

(x -h)² +(y -k)² = r² . . . . . . . circle with center (h, k) and radius r

The graph shows your circle has its center at (1, 4) and its radius is 5. Then the equation is ...

(x -1)² +(y -4)² = 25