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<u>Given</u>:
If you are dealt 4 cards from a shuffled deck of 52 cards.
We need to determine the probability of getting two queens and two kings.
<u>Probability of getting two queens and two kings:</u>
The number of ways of getting two queens is
The number of ways of getting two kings is
Total number of cases is
The probability of getting two queens and two kings is given by
Substituting the values, we get;
Simplifying, we get;
Thus, the probability of getting two queens and two kings is 0.000133
Answer: (12) ∠1 = 20° (13) ∠2 = 50° (14) ∠3 = 15° (15) UV = 80° (16) AB = 40° (17) ABC <em>or</em> 180° - CD (18) BC - 140° (19) ABC = 150°
<u>Step-by-step explanation:</u>
12) (UV - ST) = ∠1
(80 - 40) = ∠1
(40) = ∠1
20 = ∠1
13) (UV + ST) = ∠2
(70 + 30) = ∠2
(100) = ∠2
50 = ∠2
14) (VB - BS) = ∠3
(60 - 30) = ∠3
(30) = ∠3
15 = ∠3
15) (UV - ST) = ∠1
(UV - 20) = 30
UV - 20 = 60
UV = 80
16) ∠1 = arc AB
∠1 = 40
arc AB = 40
17) arc AB + arc BC = arc AC
= 180 = arc CD
18) ∠1 + ∠2 + ∠3 = 180
20 + ∠2 + 20 = 180
∠2 + 40 = 180
∠2 = 140
19) ∠1 + ∠ 2 = arc ABC
∠1 + ∠2 + ∠3 = 180
arc ABC + 30 = 180
arc ABC = 150