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Softa [21]
3 years ago
14

A rectangle has an area of 40 square units. The width of the rectangle is (n+3) and the height is n. Find the value of n.

Mathematics
1 answer:
Ne4ueva [31]3 years ago
6 0

Answer:

(n+3) × n =40

n^2 + 3n =40

n^2 + 3n - 40=0

(n+8)(n-5)=0

n=-8 or n=5

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Step-by-step explanation:

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The perimeter of a rectangular pool is 348 m.
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Answer:

The length of the rectangle is 96 \text{m}

Step-by-step explanation:

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A university found that 20% of its students withdraw without completing the introductory statistics course. Assume that 20 stude
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Answer:

a) 20.61%

b) 21.82%

c) 42.36%

d) 4 withdrawals

Step-by-step explanation:

This situation can be modeled with a binomial distribution, where p = probability of “success” (completing the course) equals 80%  = 0.8 and the probability of “failure” (withdrawing) equals 0.2.

So, the probability of exactly k withdrawals in 20 cases is given by

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a)

We are looking for

P(0;20)+P(0;1)+P(0;2) =  

\large \binom{20}{0}(0.2)^0(0.8)^{20}+\binom{20}{1}(0.2)^1(0.8)^{19}+\binom{20}{2}(0.2)^2(0.8)^{18}=

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b)

Here we want P(20;4)

\large P(20;4)=\binom{20}{4}(0.2)^4(0.8)^{16}=0.218199402\approx 0.2182=21.82\%

c)

Here we need

\large \sum_{k=4}^{20}P(20;k)=1-\sum_{k=1}^{3}P(20;k)

But we already have P(0;20)+P(0;1)+P(0;2) =0.2061 and

\large \sum_{k=1}^{3}P(20;k)=0.2061+P(20;3)=0.2061+0.205364 \approx 0.4236=42.36\%

d)

For a binomial distribution the <em>expectance </em>of “succeses” in n trials is np where p is the probability of “succes”, and the expectance of “failures” is nq, so the expectance for withdrawals in 20 students is 20*0.2 = <em>4 withdrawals.</em>

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