Its true for integers if you are using the associative property in addition or multiplication ONLY.
Answer:
y = 4
Step-by-step explanation:
8(y+4)-2(y-1)=70-3y
8y+32-2y+2=70-3y
Grouping of like terms
8y-2y+3y=70-32-2
9y=36
Divide both sides by 9
9y/9 = 36/9
9 cancels itself and 9.
y=36/9
y=4
Therefore, y = 4.
Hope it helps.
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Let the total toys be x.
The first has (1/10)x = x/10
The third child has one more toys than the first = x/10 + 1
The fourth has double of the third: = 2* (x/10 + 1) = 2x/10 + 2
Since we know that the second child has 12 more toys than the first
Therefore the Second minus First = 12.
First let us find the second.
1st + 2nd + 3rd + 4th = x
x/10 + 2nd + (x/10 + 1) + (2x/10 + 2) = x
2nd + x/10 + x/10 + 1 + 2x/10 + 2 = x
2nd + x/10 + x/10 + 2x/10 + 1 + 2 = x
2nd + 4x/10 + 3 = x
2nd = x - 4x/10 - 3
2nd = 6x/10 - 3
But recall
2nd - 1st = 12
6x/10 - 3 - x/10 = 12
6x/10 - x/10 = 12 + 3
5x/10 = 15
5x = 15 * 10
x = 15*10 /5
x = 30
So there were 30 toys in all.
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Answer: z = 264
Step-by-step explanation:
x to z = 16 to 176
x = 24 to ?
16/176 = 24/z
cross-multiply solve for z
z = 264
