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3 years ago

What is the equation of the line that has a slope of 3 and passes through the point (1, –2)?

Mathematics

1 answer:

lesya [120]3 years ago

6 0

Answer:

y = 3x - 5

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Here m = 3 , thus

y = 3x + c ← is the partial equation

To find c substitute (1, - 2) into the partial equation

- 2 = 3 + c ⇒ c = - 2 - 3 = - 5

y = 3x - 5 ← equation of line

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Simplify the expression IabI if a>0 and b>0

Brums [2.3K]

Answer:

Step-by-step explanation:

The "ab" inside absolute value has to go out positive, such as |-2|=2

Since both the a and b values are positive, the value of |ab| should be "ab"

For example:

a=2

b=3

|ab| = |2*3| = |6| = 6

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2 years ago

Prove algebraically that r = 10/2+2sinTheta is a parabola

Xelga [282]

Answer:

$y = - \frac{ 1 }{10} {x}^{2} + \frac{5}{2}$

Step-by-step explanation:

We want to prove algebraically that:

$r = \frac{10}{2 + 2 \sin \theta}$

is a parabola.

We use the relations

${r}^{2} = {x}^{2} + {y}^{2}$

and

$y = r \sin \theta$

Before we substitute, let us rewrite the equation to get:

$r(2 + 2 \sin \theta) = 10$

$r(1+ \sin \theta) = 5$

Expand :

$r+ r\sin \theta= 5$

We now substitute to get:

$\sqrt{ {x}^{2} + {y}^{2} } + y = 5$

This means that:

$\sqrt{ {x}^{2} + {y}^{2} }=5 - y$

Square:

${x}^{2} + {y}^{2} =(5 - y)^{2}$

Expand:

${x}^{2} + {y}^{2} =25 - 10y + {y}^{2}$

${x}^{2} =25 - 10y$

${x}^{2} - 25 = - 10y$

$y = - \frac{ {x}^{2} }{10} + \frac{5}{2}$

This is a parabola (0,2.5) and turns upside down.

4 0

3 years ago

What is extended form for 76.429

Zanzabum

(70x10)+(6x1)+(4x1/10)+(2x1/100)+(9x1/1000)

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2 years ago

At the circus, a clown is shot from a cannon. This situation can be modeled by the function: h = – 16t2 + 45t + 15, where 'h' is

weeeeeb [17]

Answer:

The maximum height is 46.64 feet.

Step-by-step explanation:

If we take the derivative of h whit respect to t and equal this to zero we would find the value of t which corresponds to the maximum h.

So, we have the function h(t):

$h(t)=-16t^{2} + 45t + 15$

Taking the derivative, we have:

$\frac{dh(t)}{dt}=-32t + 45=0$

Now, we solve it for t:

$t=\frac{45}{32}=1.4\: s$

Finally, we put this value of t into the original equation.

$h(t)=-16(1.4)^{2} + 45(1.4) + 15$

$h_{max}=46.64\: ft$

Therefore, the maximum height is 46.64 feet. All the given options are wrong, the one that comes closest is option A.

I hope it helps you!

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2 years ago

How do u do these percentages questions

Colt1911 [192]

Answer:

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Multiply the final number by 100.

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2 years ago

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