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tatiyna
3 years ago
8

Match each percent amount to its correct value. Tiles 15% of 30 30% of 45 60% of 7 23% of 20

Mathematics
2 answers:
Naddik [55]3 years ago
8 0
15% of 30 = 4.5
30% of 45= 13.5
60% of 7= 4.2
23% of 20= 4.6
Vlad [161]3 years ago
4 0

Answer:

15% of 30 = 4.5

30% of 45= 13.5

60% of 7= 4.2

23% of 20= 4.6

Step-by-step explanation:

We multiply each percent amount. To remove % we divide by 100

15% of 30

15/100 * 30 = 0.15 * 30=4.5

30% of 45

30/100 * 45 = 0.30 * 45=13.5

60% of 7

60/100 * 7 = 0.6 * 7=4.2

23% of 20

23/100 * 20 = 0.23 * 20=4.6

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tatyana61 [14]

Answer:

125x³ − 150x²y + 60xy² − 8y³

Step-by-step explanation:

(5x − 2y)³

₃C₀ (5x)³ (-2y)⁰ + ₃C₁ (5x)² (-2y)¹ + ₃C₂ (5x)¹ (-2y)² + ₃C₃ (5x)⁰ (-2y)³

(1) (125x³) (1) + (3) (25x²) (-2y) + (3) (5x) (4y²) + (1) (1) (-8y³)

125x³ − 150x²y + 60xy² − 8y³

7 0
3 years ago
Bank A is lending money at 6.4% interest compounded annually. The rate at Bank B is 6.3% compounded monthly, and the rate at Ban
Ad libitum [116K]

Answer:

$1596

$1597.28

$1598.33

bank A

Step-by-step explanation:

The formula for calculating compound interest:

FV = P (1 + r/m)^mn

FV = Future value  

P = Present value  

R = interest rate  

N = number of years

m = number of compounding

Bank A = $1500(1.064) = $1596

Bank B = $1500( 1 + 0.063/12)^12 = 1597.28

Bank C = $1500( 1 + 0.0635/365)^365 = $1598.33

Bank A pays the least amount of interest

8 0
3 years ago
5. Find the surface area of the prism.<br> 13 cm<br> 5 cm<br> 4 cm<br> 12 cm
erik [133]

Answer:

162 sq. cm

Step-by-step explanation:

ph+ 2b

13 + 5 + 13 + 5 * 4 + 2 * 12

36 * 4 + 24

144 +24

168

6 0
3 years ago
A 2 kg metal cylinder is supplied with 1600J of energy to heat it from 5°C to 13°C. What is the specific heat capacity of the me
Neporo4naja [7]

Answer:

c = 100\,\frac{J}{kg\cdot ^{\circ}C}

Step-by-step explanation:

According to the First Law of Thermodynamics, the heat received by the metal cylinder is equal to the change in the internal energy. That is:

Q = \Delta U

Q = m \cdot c \cdot \Delta T

The specific heat is clear in the previous expression and finally computed:

c = \frac{Q}{m\cdot \Delta T}

c = \frac{1600\,J}{(2\,kg)\cdot (13^{\circ}C-5^{\circ}C)}

c = 100\,\frac{J}{kg\cdot ^{\circ}C}

6 0
3 years ago
Does anyone know a math equation using the distributive property that equals 15
Lubov Fominskaja [6]

Answer:

3(5)=x

Explenation:

3*5 is equal to 15

5 0
2 years ago
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