Question

Find three consecutive integers whose sum in 36

Answer 1

ANSWER: 11, 12, 13

3 consecutive integers:
$x \\ x + 1 \\ x + 2$
"Sum" means Add

$x + x + 1 + x + 2 = 36$
Combine like-terms
$3x + 3 = 36$
Solve for X
$3x + 3 = 36$
Subtract 3 from both sides
$3x = 33$
Divide by 3 on both sides
$x = 11$
11 + 1 = 12
11 + 2 = 13