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Bogdan [553]
3 years ago
7

Tripling the greater of two consecutive even integers gives the same result as subtracting 10 from the lesser even integer. What

are the integers?
Mathematics
1 answer:
GalinKa [24]3 years ago
7 0
The first problem is translating the word problem into a math problem. 

Let n = one of the even integers Let n+2 = the other integer 

Now let us write an equation and solve it: 

3(n+2) = n - 10 This equation expresses what is written in the word problem. 

3(n+2) = n - 10
3n + 6 = n - 10
3n - n = -10 -6
2n = -16
n = -8
n+2 = -6 
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HACTEHA [7]
87.5 miles is the actual distance

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3 years ago
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What to the fourth power equals 0.0625?
d1i1m1o1n [39]
0.5 to the fourth power equals 0.0625.
6 0
3 years ago
A manufacturing company has the following fixed monthly costs and unit variable costs: Rent = $2,200 Utilities = $375 Variable c
valentinak56 [21]

A manufacturing company has the following fixed monthly costs and unit variable costs:

Rent = $2,200

Utilities = $375

Variable costs for materials and assembly = $13.25/unit

Monthly labor = $750

Given is the product is sold at $24.99 per unit

Let the number of units sold be x

Adding total cost = 2200+375+750=3325

Equation becomes:

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3 0
3 years ago
Components of a certain type are shipped to a supplier in batches of ten. Suppose that 50% of all such batches contain no defect
ad-work [718]

Answer:

a) P (0 defective component) = 0.5

   P( 1 defective component ) = 0.35

    P( 2 defective component ) = 0.15

b) P( 0 ) = 0

   p ( 1 ) =  1

   p ( 2 ) = 0.33

Step-by-step explanation:

p( no defective ) = 0.5

p( 1 is defective ) = 0.35

p( 2 is defective ) = 0.15

Given that 2 components are selected at random

<u>a) Given that neither component is defective </u>

Probability of 0 defective component = 0.5

P( 1 defective component ) = 0.35

P( 2 defective component ) = 0.15

<u>b) Given that one of the two tested component is defective </u>

P( 0 defective ) = 0

P( 1 defective ) = P ( \frac{x=1}{x\geq 1} ) = p( x = 1 ) / 1 - P ( x = 0 )

                                        = ( 0.5 )^1 ( 0.5 )^0 /  1 - ( 0.5)^0 (0.5)^1

                                        = 0.5 * 1 / 1 - 0.5 = 0.5 / 0.5 =  1

p ( 2 defective ) = p( x = 3 ) / 1 - P ( x = 0 )

                         = ( 0.5 )^2 ( 0.5 )^0 /  1 - ( 0.5)^0 (0.5)^2

                         = 0.25 / 0.75 = 0.33

<u />

5 0
2 years ago
Given f (x)=-3x+4 what is f (-4)<br> a.-40<br> b.-22<br> c.-1<br> d.40
FinnZ [79.3K]
F(x)=-3(x)+4
Therefore this implies that we must put the -4 where we see an X on the equation
F(-4)=-3(-4)+4
=16
6 0
3 years ago
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