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enyata [817]
2 years ago
11

Write each expression below in radical form and compute the value without using a calculator.

Mathematics
1 answer:
gregori [183]2 years ago
5 0

Assuming that an exponentiation sign is missing, all you need to know is that rational exponents work like this:

a^{\frac{b}{c}}=\sqrt[c]{a^b}

So, you have

25^{\frac{5}{2}}=\sqrt{25^5}=\sqrt{(5^2)^5}=5^5

And similarly,

81^{\frac{7}{4}}=\sqrt[4]{25^7}=\sqrt[4]{(3^4)^7}=3^7

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Evaluate the function f(p) = p^2 + 3p + 1 for p =- 2.
Anon25 [30]
(-2)^2 + 3(-2) + 1

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The angles of a triangle are 80º, 2x + 2º, and 5xº. What is the value of x?
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3 years ago
The length of a rectangle is one unit shorter than one-sixth of the width x which expression represents the perimeter of the rec
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8 0
3 years ago
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At homecoming, 125 tickets where sold. Tickets purchased for homecoming cost $20.5 without an activity card, and $15.75 with an
ale4655 [162]

Answer:

Nearly 83 students did not had activity card.

Nearly 42 students had an activity card.

Step-by-step explanation:

Total number of tickets sold at homecoming = 125

Cost of each  ticket without activity card = $20.5

Cost of each  ticket with activity card = $15.75

Total amount earned  = $2365

Let, the number of tickets sold without activity car d  = k

So, the number of tickets sold without card = (Total sold - k)

                                                                          = 125 - k

Now, according to the question:

$20.5(k) + $15.75(125 - k)  =  $2365

or, 20.5 k + 1968.5 - 15.75 k = 2365

⇒ 4.75 k = 2365 - 1968.5 = 396.5

⇒ k = \frac{396.5}{4.75 }  = 83.47

Hence, nearly 83 students did not had activity card.

So,the number of students that had activity card = 125 - 83.47 = 41.53 ~  42

Hence, nearly 42 students had an activity card.

4 0
3 years ago
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