a) 70.1 m
The ball is moving by uniformly accelerated motion, with constant acceleration 
(acceleration due to gravity) towards the ground. The height of the ball at time t is given by the equation
where 
is the height of the ball at time t=0. Substituting t=1 s, we can find the height of the ball 1 seconds after it has been dropped:
b) 3.9 s
We can still use the same equation we used in the previous part of the problem:
This time, we want to find the time t at which the ball hits the ground, which means the time t at which h(t)=0. So we have
And solving for t we find
Answer:
x = 11
Step-by-step explanation:
x - 3 = 8 add 3 to both sides
x + 3 -3 = 8 + 3 the 3s cancel each other out, 8 + 3 = 11
x = 11
Answer:
C both
Step-by-step explanation:
STEP 1:
Find % of gold members. Subtract the known % of bronze and silver members from 100%.
x= percent of gold members
x= 100% - (40% +28%)
x= 100% - 68%
x= 32% percent of gold members
STEP 2:
Find number of gold members. Multiply % of gold members by the total numbers of members (275).
x= # of gold members
x= 275 * 32%
x= 275 * 0.32
x= 88 gold members
Hope this helps! :)
Ok so remember
x^n means x times itself n times
example
x^2=x times x
x^4=x times x times x times x
so
a^3
a=7
a^3=a times itself 3 times therefor
a^3=a times a times a
subsitute 7 for a
7^3=7 times 7 times 7
7^3=343
