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Tanya [424]
3 years ago
15

Write an equation of the line passing through the given point and satisfying the given condition. Give the equation (a) in slope

-intercept form and (b) in standard form.
(6, 2); parallel to 8x - y = 4
(a) Write the equation of the line in slope-intercept form.
(Simplify your answer. Use integers or fractions for any numbers in the equation.)
Mathematics
1 answer:
Mariana [72]3 years ago
7 0

Answer:

(a) y=8x-46

(b) 8x-y=46

Step-by-step explanation:

-y=-8x+4

y=8x+4

We know that 8 is the slope, and if we need a equation parallel to this line, then it will have the same slope.

Substitute (6,2)

2=8(6)+b

2=48+b

b=-46

The final answer is y=8x-46

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X + 5y - 10 = 0<br> x = 2y - 8
ipn [44]
So since we know what x is, we can substitute it into the original equation for x like so to solve for y...

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3 0
3 years ago
A rectangular tank has length 4m, width 12m and height 3.5..i. If the tank is filled with water 2/3 of its capacity ,calculate t
ipn [44]

Answer:

The volume of the water in the tank is 112 m³

Step-by-step explanation:

The volume of the rectangular prism V = L × W × H, where

  • L is its length
  • W is its width
  • H is its height

∵ A rectangular tank has a length of 4 m, a width of 12 m, and

   a height of 3.5 m

∴ L = 4 m

∴ W = 12 m

∴ H = 3.5 m

∵ V = L × W × H

∴ The volume of the tank = 4 × 12 × 3.5

∴ The volume of the tank = 168 m³

∵ The tank is filled with water  \frac{2}{3} of its capacity

→ That means the volume of the water is  \frac{2}{3}  the volume of the tank

∵ The volume of the water = \frac{2}{3} the volume of the tank

∴ The volume of the water =  \frac{2}{3} × 168

∴ The volume of the water = 112 m³

∴ The volume of the water in the tank is 112 m³

3 0
3 years ago
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