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3 years ago

Anyone know how to do congruent triangles?

Mathematics

1 answer:

yaroslaw [1]3 years ago

7 0

Answer:

Sweetie, what's your email? I can get the document completed and sent to you

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There were 400 people at a concert. Half of them wore yellow T-shirts, 2/10 wore gray T-shirts, and the rest wore orange T-shirt

melomori [17]

Answer:

80 ppl have gray T-shirts

Step-by-step explanation:

Hope this helps! :3

Plz mark as brainliest!

7 0

3 years ago

Read 2 more answers

What is the sum of the first 200 natural numbers?

kow [346]

The sum of the first natural numbers is 20100

6 0

3 years ago

You can buy 1 pencil for $0.50. How much would a dozen cost you

Rainbow [258]

Answer:

Step-by-step explanation:

1 pencil is 50 cents. 12 pencils cost $6

3 0

3 years ago

If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the

WINSTONCH [101]

Answer:

The area of this circle is $(\frac{\pi}{2} )$ the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

Step-by-step explanation:

Area of the circle is given by;

$A_c = \frac{\pi d^2}{4}$

Area of the square is given by;

$A_s = L^2$

relationship between the edge length of the square, d, and length of its side, L,

$d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}$

But area of the square , $A_s = L^2$

$d = \sqrt{2A_s}$

Then, the area of the square in terms of the edge length is given by;

$A_s = \frac{d^2}{2}$

Area of the circle in terms of area of the square is given by;

$A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )$

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

$\phi _{circle} = E.(\frac{\pi d^2}{4})$

Flux through the surface of the square is given by;

$\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )$

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

5 0

4 years ago

Solve using equivalent ratios.

jeyben [28]

Answer:

Step-by-step explanation:

3 x 5 = 15 so 2 x 5 = 10

5 0

3 years ago