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2 years ago

Somebody help me with the question

Mathematics

1 answer:

zloy xaker [14]2 years ago

4 0

Answer is 3
Step by step exploration

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How do you find the radius of a circle with a circumference of 12pi

sergejj [24]

Answer:

Step-by-step explanation:

The circumference of a circle is $2\pir$ $\pi r$ , so $12\pi=2\pi r\\12=2r\\r=6$ . We can use this because the area of a circle is $\pi r^2$ . Thus, $\pi*6^2=36\pi$ .

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3 years ago

Plzzzzzzzzzzz Help me

Sati [7]

-3 < 0 Because -3 is less than 0.

Hope this helps ;P

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3 years ago

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Use the Remainder Theorem to find the remainder: (16x^4 – 8x^3 – 4x + 1) ÷ (2x + 1)

vodka [1.7K]

Answer:

Step-by-step explanation:

This illustrates the Remainder Theorem. If a polynomial f(x) is divided by x−a , the remainder is the constant f(a) , and f(x)=q(x)⋅(x−a)+f(a) , where q(x) is a polynomial with degree one less than the degree of f(x) . Synthetic division is a simpler process for dividing a polynomial by a binomial.

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3 years ago

What is the diameter of a circle that has an area of 49pie

tester [92]

There would not be one

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3 years ago

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If N is the population of the colony and t is the time in days, express N as a function of t. Consider Upper N 0 is the origina

lesya [120]

Answer:

(a) $N(t)=Noe^{kt}$

(b)5,832 Mosquitoes

Step-by-step explanation:

(a)Given an original amount $N_o$ at t=0. The population of the colony with a growth rate $k \neq 0$ , where k is a constant is given as:

$N(t)=Noe^{kt}$

(b)If $N_o=1000$ and the population after 1 day, N(1)=1800

Then, from our model:

N(1)=1800

$1800=1000e^{k}\\$Divide both sides by 1000\\e^{k}=1.8\\$Take the natural logarithm of both sides\\k=ln(1.8)$

Therefore, our model is:

$N(t)=1000e^{t*ln(1.8)}\\N(t)=1000\cdot1.8^t$

In 3 days time

$N(3)=1000\cdot1.8^3=5832$

The population of mosquitoes in 3 days time will be approximately 5832.

(c)If the population N(t)=20,000,we want to determine how many days it takes to attain that value.

From our model

$N(t)=1000\cdot1.8^t\\20000=1000\cdot1.8^t\\$Divide both sides by 1000\\20=1.8^t\\$Convert to logarithm form\\Log_{1.8}20=t\\\frac{Log 20}{Log 1.8}=t\\ t=5.097\approx 5\; days$

In approximately 5 days, the population of mosquitoes will be 20,000.

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2 years ago

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