a=-2, b=3, c=-4, d=5
abc-d
abc means multiply those 3 together
so -2 x 3 x -4 = 24
24-5 = 19
answer is 19
Answer:
= 1.56
Step-by-step explanation:
Hello!
You have two independent samples of fertilizers from distributor A and B, and need to test if the average content of nitrogen from fertilizer distributed by A is greater than the average content of nitrogen from fertilizer distributed by B.
Sample 1
X₁: Content of nitrogen of a fertilizer batch distributed by A
n₁= 4 batches
Sample mean X₁[bar]= 23pound/batch
σ₁= 4 poundes/batch
Sample 2
X₂: Content of nitrogen of a fertilizer batch distributed by B
n₂= 4 batches
Sample mean X₂[bar]= 18pound/batch
σ₂= 5 pounds/batch
Both variables have a normal distribution. Now since you have the information on the variables distribution and the values of the population standard deviations, you could use a pooled Z-test.
Your hypothesis are:
H₀: μ₁ ≤ μ₂
H₁: μ₁ > μ₂
The statistic to use is:
Z= <u> X₁[bar] - X₂[bar] - (μ₁ - μ₂) </u>~N(0;1)
√(δ²₁/n₁ + δ²₂/n₂)
=<u> </u>(<u>23 - 18) - 0 </u> = 1.56
√(16/4 + 25/4)
I hope this helps!
<h3>
Answer:</h3>

<h3>
Explanation:</h3>
<u>Sequence</u>: 1.2, 0.4, -0.4, – 1.2, -2,...
See that with every next term, the integers are decreasing by 0.8
- So, common difference (d) = -0.8
<u>recursive formula</u> : 

Answer:
k = (1 , 4)
Step-by-step explanation:
here's your solution
==> k^2 - 5k + 4. [ is expression ]
==> by using middle term split
==> k^2 - 4k - k + 4
==> taking common from each
==> k(k - 4) - 1 (k - 4)
==> (k - 1) , (k - 4).
==> k - 1 = 0
==> k = 1
==> k - 4 = 0
==> k = 4
hence , k = (1 , 4)
hope it helps
Answer:
-9/11
Step-by-step explanation:
slope is change in y/change in x
change in y is 9 (12-3)
change in x is -11 (-17--8)
slope is -9/11