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8_murik_8 [283]
3 years ago
8

What is the perimeter of triangle LMN

Mathematics
1 answer:
Gennadij [26K]3 years ago
4 0
Lmn has sides measuring 7 m and 6 m and a perimeter of 16 m.
But if you were asking for the area it would be 3 m
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What is the next second step in solving the following equation -3x+5=20
denpristay [2]

Answer:

x=-5

Step-by-step explanation:

first you subtract the positive 5 from the 20.

second you divide negative 3x into 15

the answer you get should be x=-5

5 0
4 years ago
One of the legs of a right triangle is twice as long as the other, and the perimeter of the triangle is 28. Find the length of t
Nutka1998 [239]

1) If we let the lengths of the legs be x and 2x, then by the Pythagorean theorem,

x+2x+\sqrt{x^{2}+(2x)^{2}}=28\\3x+x\sqrt{5}=28\\x(3+\sqrt{5})=28\\x=\frac{28}{3+\sqrt{5}} \cdot \frac{3-\sqrt{5}}{3-\sqrt{5}}=21-7\sqrt{5}

This means that the length of the hypotenuse is:

\sqrt{5}(21-7\sqrt{5})=\boxed{21\sqrt{5}-35}

2) (Diagram attached) We know that

\cos 51^{\circ}=\frac{x}{58}\\x=58 \cos 51^{\circ} \approx \boxed{36.5}  (in cm)

3) From the Pythagorean identity,

\sin^{2}\left (\arccos \frac{5}{13} \right)+\cos^{2} \left (\arccos \frac{5}{13} \right)=1\\\left(\frac{5}{13} \right)^{2}+\sin^{2} \left (\arccos \frac{5}{13} \right)=1\\\frac{25}{169}+\sin^{2} \left (\arccos \frac{5}{13} \right)=1\\\sin^{2} \left (\arccos \frac{5}{13} \right)=\frac{144}{169}\\\sin \left (\arccos \frac{5}{13} \right)=\boxed{\frac{12}{13}}

4) \frac{\pi}{6}

7 0
2 years ago
Find the missing length. Give all answers in the simplest radical form.​
Solnce55 [7]

Answer:

x = 2\sqrt{74}

Step-by-step explanation:

Since the triangle is right use Pythagoras' identity to solve for x

The square on the hypotenuse is equal to the sum of the squares on the other two sides, that is

x² = 14² + 10² = 196 + 100 = 296

Take the square root of both sides

x = \sqrt{296} = 2\sqrt{74}

8 0
3 years ago
5x + 3y = -4<br> y - 2x = 6<br> By substitution
Assoli18 [71]

Answer:

Hello!

Solve the following system of equations by the substitution method. 5x = y + 6 2x - 3y = 4 What is the value of the y-coordinate?

Solving:

5x = y + 6 (I)

2x - 3y = 4 (II)

god i hope i helped if i did tell me so in not plz still tell me and i will make it better see ya

4 0
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The first answer is 1 and the second is 0.83333.
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4 years ago
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