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Paul [167]
3 years ago
11

The Reliable Car dealership sells cars and trucks. The cars and trucks

Mathematics
1 answer:
S_A_V [24]3 years ago
4 0
The probilitu would be 1/3 becouse they are all evan and yeah
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I HAVE 10 MIN LEFT CAN SOMEONE HELP ME WITH A FEW OF THESE OR ALL OF EM?
FinnZ [79.3K]
I will help you but I need to know what you need help with , find the area or volume?
4 0
2 years ago
Does anyone know how to solve this?
KATRIN_1 [288]

Answer:

<30,-20>

Step-by-step explanation:

4u + 2v

4< 6,-4> + 2< 3,-2>

<24,-16> + < 6,-4>

<30,-20>

4 0
2 years ago
The dimensions of a triangular prism are shown.
Serhud [2]

9514 1404 393

Answer:

  B.  32 square inches

Step-by-step explanation:

Each of the two triangular faces has an area of ...

  A = (1/2)bh = (1//2)(6 in)(4 in) = 12 in²

The lateral surface area is the product of the prism height (0.5 in) and the perimeter of the base.

  LA = (0.5 in)(5 in +5 in + 6 in) = 8 in²

So, the total area is the area of the two base and the lateral area:

  SA = 2A +LA

  SA = 2(12 in²) +8 in² = 32 in²

The surface area of the prism is 32 square inches.

7 0
3 years ago
Read 2 more answers
See attachment below
KatRina [158]

Answer: Third Option

x=1.469743

Step-by-step explanation:

We have the following exponential equation

3^{x+1}=15

We must solve the equation for the variable x

To clear the variable x apply the log_3 function on both sides of the equation

log_3(3^{x+1})=log_3(15)

Simplifying we get the following:

x+1=log_3(15)

To simplify the expression log_3 (15) we apply the base change property

log_b(y)=\frac{log(y)}{log(b)}

This means that:

log_3 (15)=\frac{log(15)}{log(3)}

Then:

x+1=\frac{log(15)}{log(3)}

x=\frac{log(15)}{log(3)}-1

x=1.469743

6 0
2 years ago
Which technique is most appropriate to use to solve each equation? Drag the name of the technique into the box to match each equ
NemiM [27]
For the first equation, the answer is C) completing the square.
For the second equation, the answer is B) zero product property.

For the first equation, we can easily complete the square by finding half of b and squaring it; then we can take the square root of both sides and solve the equation.

For the second equation, since it is already factored, we use the zero product property to solve it.
7 0
3 years ago
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