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2 years ago

Select the story problem that this division problem represents 2/3/1/6

Mathematics

1 answer:

tatyana61 [14]2 years ago

8 0

Answer:

Step-by-step explanation:

Looking at the problem we see that in problem A Betsy jogs in a rectangular course that has 1/6 mile. The question wants the width. The width equals W=A/L or area over length.

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Hamdi lives 452 miles from her

scZoUnD [109]

Answer:

It's 317 miles.

Step-by-step explanation:

You just take the amount of miles it is from her grandparents house and the amount of miles to her cousins house and then you subtract them.

452-135=317 miles apart.

7 0

2 years ago

Sophia's school has 23 classrooms. Each classroom has 10 tables. How many tables are there in the school?

amid [387]

If there is 23 classrooms and each has 10 then you would have to times 23 by 10 - 23x10=230

4 0

2 years ago

Read 2 more answers

2+2-8-*456*7524+7+46426+*545/65/6213-543+3112+91456+210256488765454<br><br> Answer within 10 min

zvonat [6]

Answer:

My calculator said error and i tried looking it up it said error too. I'm sorry I tried, you'll have to do it by hand

Step-by-step explanation:

5 0

2 years ago

A string passing over a smooth pulley carries a stone at one end. While its other end is attached to a vibrating tuning fork and

nasty-shy [4]

Answer:

correct option is C) 2.8

Step-by-step explanation:

given data

string vibrates form = 8 loops

in water loop formed = 10 loops

solution

we consider mass of stone = m

string length = l

frequency of tuning = f

volume = v

density of stone = $\rho$

case (1)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

so here

$l = \frac{8 \lambda _1}{2}$ ..............1

$l = 4 \lambda_1\\\\\lambda_1 = \frac{l}{4}$

and we know velocity is express as

velocity = frequency × wavelength .....................2

$\sqrt{\frac{Tension}{mass\ per\ unit \length }}$ = f × $\lambda_1$

here tension = mg

$\sqrt{\frac{mg}{\mu}}$ = f × $\lambda_1$ ..........................3

and

case (2)

when 8 loop form with 2 adjacent node is $\frac{\lambda }{2}$

$l = \frac{10 \lambda _1}{2}$ ..............4

$l = 5 \lambda_1\\\\\lambda_1 = \frac{l}{5}$

when block is immersed

equilibrium eq will be

Tenion + force of buoyancy = mg

T + v × $\rho$ × g = mg

and

T = v × $\rho$ - v × $\rho$ × g

from equation 2

f × $\lambda_2$ = f × $\frac{1}{5}$

$\sqrt{\frac{v\rho _{stone} g - v\rho _{water} g}{\mu}} = f \times \frac{1}{5}$ .......................5

now we divide eq 5 by the eq 3

$\sqrt{\frac{vg (\rho _{stone} - \rho _{water})}{\mu vg \times \rho _{stone}}} = \frac{fl}{5} \times \frac{4}{fl}$

solve irt we get

$1 - \frac{\rho _{stone}}{\rho _{water}} = \frac{16}{25}$

relative density $\frac{\rho _{stone}}{\rho _{water}} = \frac{25}{9}$

relative density = 2.78 ≈ 2.8

so correct option is C) 2.8

3 0

3 years ago

If money in a savings account earned 8% interest per annum, how much nterest would be earned on $150.00 over three years?

Pani-rosa [81]

Answer:

$36

Step-by-step explanation:

Given :

Interest rate, r = 8% = 0.08

Principal, P = 150

Time, t = 3 years

Simple interest = (principal * rate * time)

Simple interest = (150 * 0.08 * 3)

Simple interest = $36

7 0

3 years ago