Ask question

Ask question

All categories

iogann1982 [59]

3 years ago

7

please answer this question A bakery uses 300 pounds of flour to make 120 wedding cakes of the same size. At this rate how many

pounds of flour are needed to make 1 wedding cake?

1 answer:

saw5 [17]3 years ago

4 0

Answer:

0.4 pounds

Step-by-step explanation:

300 divided by 120= 0.4, meaning you need 0.4 pounds of flour for 1 cake

You might be interested in

Use the general slicing method to find the volume of the following solids. The solid whose base is the region bounded by the cur

Y_Kistochka [10]

Answer:

The volume is $V=\frac{64}{15}$

Step-by-step explanation:

The General Slicing Method is given by

<em>Suppose a solid object extends from x = a to x = b and the cross section of the solid perpendicular to the x-axis has an area given by a function A that is integrable on [a, b]. The volume of the solid is</em>

$V=\int\limits^b_a {A(x)} \, dx$

Because a typical cross section perpendicular to the x-axis is a square disk (according with the graph below), the area of a cross section is

The key observation is that the width is the distance between the upper bounding curve $y = 2 - x^2$ and the lower bounding curve $y = x^2$

The width of each square is given by

$w=(2-x^2)-x^2=2-2x^2$

This means that the area of the square cross section at the point x is

$A(x)=(2-2x^2)^2$

The intersection points of the two bounding curves satisfy $2 - x^2=x^2$ , which has solutions x = ±1.

$2-x^2=x^2\\-2x^2=-2\\\frac{-2x^2}{-2}=\frac{-2}{-2}\\x^2=1\\\\x=\sqrt{1},\:x=-\sqrt{1}$

Therefore, the cross sections lie between x = -1 and x = 1. Integrating the cross-sectional areas, the volume of the solid is

$V=\int\limits^{1}_{-1} {(2-2x^2)^2} \, dx\\\\V=\int _{-1}^14-8x^2+4x^4dx\\\\V=\int _{-1}^14dx-\int _{-1}^18x^2dx+\int _{-1}^14x^4dx\\\\V=\left[4x\right]^1_{-1}-8\left[\frac{x^3}{3}\right]^1_{-1}+4\left[\frac{x^5}{5}\right]^1_{-1}\\\\V=8-\frac{16}{3}+\frac{8}{5}\\\\V=\frac{64}{15}$

5 0

3 years ago

I need help with volumes of cones

irinina [24]

search up on google volume of a cone and type in your numbers and it will show you the answers

4 0

3 years ago

20 POINTSSS AND I WILL GIVE BRAINLIEST !!

inessss [21]

I think it’s Step 2 your welcome

7 0

2 years ago

In order to earn extra money during the summer , omar is babysitting . The amount of money depends on the number of hours he bab

luda_lava [24]

M is dependent and h is independent
m=money and h=hours, p =money per hour
m=ph

6 0

3 years ago

Please help me. I'm stupid.

Gwar [14]

Answer:

$\displaystyle 36\:units$

Step-by-step explanation:

Split up this Isosceles, Right Triangle into two congruent smaller right triangles. The reflexive side [the line that splits them apart] is 6 units, and both legs are 8 units, leaving the hypotenuses to AUTOMATICALLY be 10 units, according to the Pythagorean Theorem:

$\displaystyle a^2 + b^2 = c^2 \\ \\ 6^2 + 8^2 = 10^2 \\ \\ 36 + 64 = 100 \\ \\ 100 = 100$

With this Pythagorean Triple, we know that our dimensions are correct. Now, to find the perimeter, just add up all the sides EXCEPT for the divider:

$\displaystyle 2[10] + 2[8] = 20 + 16 = 36$

I am joyous to assist you anytime.

3 0

3 years ago