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Olenka [21]
3 years ago
5

The dot plots show rainfall total for several spring storms in highlands areas an lowlands areas what is the median rainfall for

the highland storms

Mathematics
2 answers:
tankabanditka [31]3 years ago
8 0

*See attached picture showing the dot plots referred to

Answer:

16mm

Step-by-step Explanation:

Given the dot plot showing rainfall for Highlands storms, we can find out the median rainfall for Highlands storms by mere observing the dot plot and locating where the middle value falls within the data set that is represented on the dot plot.

Thus, we have 44 data sets that is being represented on the plot, with one dot representing one data set for rainfall. This means, since the total number of data set is even, our median lies between the 22nd and the 23rd dot or data set that is being plotted.

From the dot plot for Highlands, the 22nd and 23rd dots are 16 and 16 respectively.

Therefore, median rainfall for Highland storms = (16 + 16) ÷ 2 = 16.

Pavlova-9 [17]3 years ago
6 0

Answer:

Median for Highland Storms: 16MM

Median for Lowland Storms: 12MM

Step-by-step explanation:

Edge 2020, And I got it correct on my second try. So these are 100% correct.

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Answer:

a) 29.4-1.96\frac{7}{\sqrt{10}}=25.06  

29.4+1.96\frac{7}{\sqrt{10}}=33.74  

So on this case the 95% confidence interval would be given by (25.06;33.74)  

b) z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988  

p_v =P(z>1.988)=0.0234    

If we compare the p value and the significance level given \alpha=Step-by-step explanation:Previous conceptsA confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".  &#10;The margin of error is the range of values below and above the sample statistic in a confidence interval.  &#10;Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  &#10;Part a&#10;Data given: 30 30 42 35 22 33 31 29 19 23&#10;We can calculate the sample mean with the following formula:[tex] \bar X = \frac{\sum_{i=1}^n X_i}{n}= 29.4 the sample mean

\mu population mean (variable of interest)  

\sigma=7 represent the population standard deviation  

n=10 represent the sample size  

95% confidence interval  

The confidence interval for the mean is given by the following formula:  

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)  

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96  

Now we have everything in order to replace into formula (1):  

29.4-1.96\frac{7}{\sqrt{10}}=25.06  

29.4+1.96\frac{7}{\sqrt{10}}=33.74  

So on this case the 95% confidence interval would be given by (25.06;33.74)  

Part b

What are H0 and Ha for this study?  

Null hypothesis:  \mu \leq 25  

Alternative hypothesis :\mu>25  

Compute the test statistic

The statistic for this case is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

We can replace in formula (1) the info given like this:  

z=\frac{29,4-25}{\frac{7}{\sqrt{10}}}=1.988  

Give the appropriate conclusion for the test

Since is a one side right tailed test the p value would be:  

p_v =P(z>1.988)=0.0234  

Conclusion  

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis.    

8 0
3 years ago
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