Write the product of -2 and (3 - 5a) as the sum of two factors

Calling All Mathematicians Please Please Please Help On This Question!!!!!!!!!!!!!!

Fiesta28 [93]

Use the distance formula, AB=√[(1-(-9)]²+[(-1-(-3)]=√[100+4]=√104
use the same formula, AC=√52, BC=√52
AC²+BC²=52+52=104=AB²
Yes, it is a right triangle.

8 0

3 years ago

Students in 10th and 11th grade were asked whether they have a job. The raw data was converted to relative frequencies and recor

Softa [21]

Answer:

a)- Given that a student is a 10th grader, there is a 14% chance he or she has a job.

Step-by-step explanation:

Option (a) is correct here because Relative frequency means the probability of occurrence or number of time-specific event occurs to the total event.

Option (b) is not correct because We already know that student is in 10th or 11th grade, after that we get to know about 14% chance.

Option (c) & (d) are clearly not possible.

5 0

3 years ago

Read 2 more answers

What percent is equivalent to 18/30

FrozenT [24]

18 / 30 =

60 percent

4 0

3 years ago

Read 2 more answers

Round 0.5289 to the nearest thousandth.

Anit [1.1K]

Answer:

0.5289 to the nearest thousandth is 0.529.

Step-by-step explanation: If a number is less than 5, round down, but if a number is 5 or more, round up. The digit after the thousandths place is the digit we should look at to answer the question and it is 9, so we round up from 0.528 or 0.529. So, the answer is 0.529.

7 0

3 years ago

Let us have four distinct collinear points $a,$ $b,$ $c,$ and $d$ on the cartesian plane. the point $c$ is such that $\dfrac{ab}

Deffense [45]

Start with a line segment connecting two points, A and B. $\dfrac{DA}{BA}=3$ means DA is 3 times longer than BA. Clearly, D cannot fall between A and B because that would mean DA is shorter than BA. So there are two possible locations where D can be placed on the line relative to A and B.

But with $\dfrac{DB}{BA}=2$ , or the fact that DB is 2 times longer than BA, we can rule out one of these positions; referring to the attachment, if we place D to the left of A, then DB would be 4 times longer than BA.

Finally, $\dfrac{AB}{CB}=\dfrac12$ , so that CB is 2 times longer than AB. Again we have two possible locations for point C (it cannot fall between A and B), but one of them forces C to occupy the same point as D. However, A, B, C, D are distinct, so C must fall to the left of A.

Now let $d$ be the length of AB. Then the length of CD in terms of $d$ is $4d$ . We have the coordinates of C and D, and the distance between them is $\sqrt{(4-0)^2+(0-4)^2}=4\sqrt2$ . So

$4d=4\sqrt2\implies d=\sqrt2$

The slope of the line through C and D is

$\dfrac{0-4}{4-0}=-1$

and so the equation of the line through these points is

$y-4=-(x-0)\implies x+y=4$

So the coordinates of A are $(x,y)=(x,4-x)$ . The distance between C and A is $d=\sqrt2$ , so we have

$\sqrt{(x-0)^2+(4-x-4)^2}=\sqrt{2x^2}=|x|\sqrt2=\sqrt2\implies|x|=1$

Since A falls to the right of C (in the $x,y$ plane, not just in the sketch), we know to take the positive value $x=1$ . Then the $y$ coordinate is $y=4-1=3$ .

All this to say that A is the point (1, 3), so

$2x+y=2+3=5$

5 0

3 years ago