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Daniel [21]
3 years ago
6

Please help me I need help

Mathematics
1 answer:
Llana [10]3 years ago
7 0

9514 1404 393

Answer:

  F.  x ≤ -5

Step-by-step explanation:

Translating the diagram to more conventional symbols, we have ...

  4x +12 ≤ -8

  4x ≤ -20 . . . . . . . subtract 12 from both sides

  x ≤ -5 . . . . . . . . . divide both sides by 5

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Please don’t comment if you don’t know both answers <br> bc I’ll report you
GuDViN [60]
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Solve system with substitution
SpyIntel [72]

Answer:

The cost of 1 Rose Bush= $ 8

The cost of 1 Shrub =  $12.

Step-by-step explanation:

The cost of 11 rose bushes and 4 shrubs =  $136

The cost of 2 rose bushes and 11 shrubs =  $148

Let the cost of one rose bush =  $x

and the cost of one shrub  =  $ y

Now, according to the question:

11 x + 4 y = 136

and 2 x + 11 y  = 148

From (1), we get that 11x  = 136 - 4y

or, x = \frac{136 - 4y}{11}

Substitute this value of x in equation (2), we get

2 x + 11 y  = 148  \implies 2( \frac{136 - 4y}{11})  + 11y  = 148

or, ( \frac{272 - 8y}{11})  + 11y  = 148  \implies 272 - 8y + 121y = 1628

or, 113 y = 1356

or, y = 1356/113 = 12

⇒ y = 12, So x  =  \frac{136 - 4y}{11}  = \frac{136 -12(4)}{11} = \frac{136 - 48}{11}  = 8

or, x  =8 and  y = 12 is the solution of the above system.

Hence, the cost of 1 rose bush  = $x = $8

and  The cost of 1 shrub = $ y = $12.

4 0
3 years ago
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